determine whether the DE is exact: y^2dx - x^2dy=0

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determine whether the DE is exact: y^2dx - x^2dy=0

Mathematics
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[S] dy/(y^2) = [S] dx/(x^2)
DE is exact? whats that mean? :)
using the exact method

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ahh..... and what is the exact method? :)
use the test for exactness: take partial derivative of M with respect to y and partial derivative of N with respect to x and see if they provide the same answer .....its more complicated. the exact method is a part of solving differential equations
ive seen that in the textbooks before, but cant recall the details of it :)
a DE is exact if partial derivative of coefficient of x with respect to y is equal to partial derivative of coeff of y with respect to x. It an equation is exact there is an easy method to solve it.
correction; coefficients of dx and dy

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