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anonymous

  • 5 years ago

determine whether the DE is exact: y^2dx - x^2dy=0

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  1. amistre64
    • 5 years ago
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    [S] dy/(y^2) = [S] dx/(x^2)

  2. amistre64
    • 5 years ago
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    DE is exact? whats that mean? :)

  3. anonymous
    • 5 years ago
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    using the exact method

  4. amistre64
    • 5 years ago
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    ahh..... and what is the exact method? :)

  5. anonymous
    • 5 years ago
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    use the test for exactness: take partial derivative of M with respect to y and partial derivative of N with respect to x and see if they provide the same answer .....its more complicated. the exact method is a part of solving differential equations

  6. amistre64
    • 5 years ago
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    ive seen that in the textbooks before, but cant recall the details of it :)

  7. anonymous
    • 5 years ago
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    a DE is exact if partial derivative of coefficient of x with respect to y is equal to partial derivative of coeff of y with respect to x. It an equation is exact there is an easy method to solve it.

  8. anonymous
    • 5 years ago
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    correction; coefficients of dx and dy

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