2x1/-6x1/-5 please help!!

- anonymous

2x1/-6x1/-5 please help!!

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- anonymous

the / is a division sign

- anonymous

Can u pls type it using the equation tab below. It is difficult to understand it like this

- anonymous

well h/o.. write ur answer as a fraction in simplest form. does this help?
2 X 1 X 1
--- ---
-6 -5

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## More answers

- anonymous

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- anonymous

The answer is 1/15

- anonymous

great! now how ab

##### 1 Attachment

- anonymous

When you have such multiplication of fractions, follow the rule :
(Here N means numerator and D means denomination)
N1 x N2 x N3 N1 x N2 x N3
-- -- -- = -------------
D1 D2 D3 D1 X D2 X D3

- anonymous

ohh ok

- anonymous

Now using this formula try to solve yourself and I'll check if it is correct

- anonymous

do u multiply the -7 with the N or D?

- anonymous

in the 2nd problem?

- anonymous

You can treat it as -7
--
1
So you multiply -7 with the numerator group

- anonymous

oh okay

- anonymous

soo
98
--
-54

- anonymous

Correct!!
But something more needs to be done

- anonymous

simplify? idk how to do that with this fraction

- anonymous

First, we hv to reduce it to lowest terms
Second, make the denominator positive

- anonymous

OK,
Both are even nos and hence divisible by 2
So go ahead and divide both by 2

- anonymous

Then multiply this by -1/-1 to make the denominator positive

- anonymous

Done????

- anonymous

49 -1
--- x ___
-27 -1

- anonymous

soo that means the answer is this?
-49
---
27

- anonymous

BINGO !!!!
You got the hang of it !!

- anonymous

yay! is that simplest form?

- anonymous

Now I'll teach you how to reduce it to lower terms easily

- anonymous

okay :)

- anonymous

Yes it is because 49 is 7 x 7
and 27 is 3 x 3 x 3
So both numbers do not hv any common factor left

- anonymous

okay thank u

- anonymous

your question was 2 x -7 x -7
--- ---
9 -6

- anonymous

We modify it to 2 x -7 x -7
--- --- ---
9 1 - 6

- anonymous

Now we can easily see that 2 in the numerator of first fraction and 6 in the denominator of third fraction are both divisible by 2 and so we divide them by 2 to get
1 x -7 x -7
--- --- ---
9 1 -3

- anonymous

Following me???

- anonymous

ok now i have another ?
is -3(3x-u)+(2u-4x) simplified to -9?

- anonymous

yes

- anonymous

Now you can clearly see that numerators on top and denominators at bottom cannot be cross -cut as they do not have common factors
so now multiply all numerators and all denominators and basically shift the - sign to the numerator

- anonymous

is that the simplified expression to that expression?
yes.thank u for explaining that to me.

- anonymous

Yes, when u hv many fractions, you can use cross-cutting to cancel out common factors
Now to yr second question.....
-3(3x-u)+(2u-4x) = -9x + 3u + 2u - 4x
= -9x - 4x + 3u + 2u
= - 13x + 5u

- anonymous

How did u arrive at -9 ??

- anonymous

-3(-3x-u)+(2u-4x)
-3(-3x)+1+(-4x)
-3+1+-7

- anonymous

i did it wrong

- anonymous

but i was supposed to distribute

- anonymous

Yes, when you have an expression like -3(3x-u), you have to first use the DISTRIBUTIVE LAW to open the bracket and then solve further

- anonymous

wait..it said that wasn't correct.

- anonymous

What's the ans u hv????

- anonymous

i got 5x-1u

- anonymous

1u ? :|

- anonymous

-3(-3x-u) + (2u-4x)
(9x-3u) + (2u-4x)
-1u + 5x
5x + -1u
5x-1u

- anonymous

Then u gave me the wrong question the first time around!!!! Go and check....

- anonymous

i did! i'm sorry!! ahaha i put 3 and it was supposed to be -3 i think

- anonymous

but am i correct (with the problem i just did)

- anonymous

Well, one can always make mistakes while typing......
No, your answer is not correct. See my working below...
-3(-3x-u) + (2u-4x) = 9x + 3u + 2u - 4x
= 9x - 4x + 3u + 2u
= 5x + 5u
= 5 (x + u)

- anonymous

"5x-1u " :\
why is there a 1 in front of the u ?

- anonymous

you write "5-u" , no need for the 1 , it just makes it look messy , whenever I mark maths if I see anyone write coeffiecent of 1 then they lose marks

- anonymous

But her answer is wrong anyway.....

- anonymous

yeh , doesnt mean you cant correct notation

- anonymous

agreed :)

- anonymous

But if you deduct marks for this, I feel u r too harsh on the students. Just putting a circle and remarking shud do th job

- anonymous

yeah but for my learning purposes i sometimes put the -1 so i don't lose track.

- anonymous

but anyway..i see what u did harkirat ... idk what the crap i did! haha

- anonymous

No sweat, we all learn by making mistakes and correcting them

- anonymous

yeh, probably for like year4 kids in primary you wouldnt mark down , but if they are in high school and writting coefficents of 1 then there is something wrong , it makes you looks stupid putting 1u , because that shows the marker that you dont know that 1 times u =u

- anonymous

@elecengineer
R u located in the US??

- anonymous

australia

- anonymous

R u an Indian by any chance??

- anonymous

no, not asian either

- anonymous

but alot of the electrical engineering lecturers at my uni are

- anonymous

im white lol

- anonymous

Just asking, hope u didn't mind

- anonymous

you shouldn't call students stupid...they mean the same thing. -1u and -u...just because it's marked differently doesnt mean you should mark down a grade..the answer is not wrong technically. its like your punishing your students because their teacher is a neat freak.

- anonymous

I'm an Indian and I know teachers here (in India) r very harsh with such things and penalise even small things

- anonymous

C'mon lauren, thats not nice

- anonymous

i dnt care what they say ^

- anonymous

but hey i'm just a first year college student. what do i know? but anywho the answer 5x+5u was correct!!! yayy!!
i'm sorry. i'm just the type of person who says what i feel. i'm sorry if i offended you. just different opinions that is all.

- anonymous

but seriously, if you are in high school you shouldnt need to write the 1s

- anonymous

you are first year of uni , 19yrs old and you still write the 1s , you should have dropped that a long time ago lol

- anonymous

C'mon friends, let us change the topic

- anonymous

Do u need to ask anything else lauren??

- anonymous

agreed. i don't like negativity. and yes...one sec please.

- anonymous

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- anonymous

im not negative , just stating the facts, and I would be very surprised if a uni tutor doesnt mark down because of bad notation , its one thing to get the right answer, but you also need to express yourself confidently

- anonymous

if you click the link it makes it bigger.

- anonymous

^ thats first year uni math?
cant be

- anonymous

what do you mean by "college"

- anonymous

i'm in Math098...i'm not the best math student and have never really been good at math or liked it...but it is a lower level of math.

- anonymous

but i do go to a university.

- anonymous

k... thats like the stuff we do in year8 in high school in australia

- anonymous

lauren, u do it and tell me the ans
I'll confirm if it is ok
This is a simple one, just b careful while using the Dist. LAW

- anonymous

i got -11y+8

- anonymous

wow :p

- anonymous

Bingo !! Its correct , the working as follows
-4 (3y - 2) + y = -12y + 8 + y
= - 11y + 8

- anonymous

=)

- anonymous

I should go fetch a really hard version of these from one of my high maths text books , these are far too easy :p

- anonymous

something much more complex

- anonymous

k u go do that. lol

- anonymous

Ok lauren, give this a try
2(x+ 3y) -7(2y - 5z) + 3(2x - 3y +z)

- anonymous

Focus and you'll do it right

- anonymous

k h/o

- anonymous

nah , just expanding is no fun, I am talking really messy algebraic fractions , with fractions inside fraction etc , really fun :p

- anonymous

C'mon elecengineer, giv her a break
U r suggesting a mosquito weight fights Mike Tyson :D

- anonymous

8x-23y+38z

- anonymous

not quite

- anonymous

lauren, redo it and keep + and - signs in mind while expanding

- anonymous

it wasnt the signs that caused the mistake :|

- anonymous

8x-17y+38z
and i missed one of the y terms while comining like terms.

- anonymous

combining*

- anonymous

Good, u did it!!

- anonymous

cool :)

- anonymous

Maths needs constant/regular/focussed practice

- anonymous

Find more such sums and keep doing them

- anonymous

thanks harkirat....are these like terms?
8x and 8x^2

- anonymous

no

- anonymous

do u know why??

- anonymous

bc of the exponent

- anonymous

Correct,
In Algebra, for like terms we look at the variables and not the coefficient

- anonymous

For eg if u hv these four terms
-5 x^2y^5z , 7x^2y^5 , 2zy^5x^2 , -11 xyz

- anonymous

k got it

- anonymous

The two like terms here are
-5 x^2y^5z , 2zy^5x^2 becoz both hv x^2 y^5 and z as algebraic factors

- anonymous

Got it??

- anonymous

yep!

- anonymous

So just look at varible and their powers
If two terms have all variables same and their powers same, then they r like, irrespective of their coefficients

- anonymous

here the operative word is ALL
ALL variables same and their respective powers same

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