anonymous
  • anonymous
2x1/-6x1/-5 please help!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
the / is a division sign
anonymous
  • anonymous
Can u pls type it using the equation tab below. It is difficult to understand it like this
anonymous
  • anonymous
well h/o.. write ur answer as a fraction in simplest form. does this help? 2 X 1 X 1 --- --- -6 -5

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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
The answer is 1/15
anonymous
  • anonymous
great! now how ab
1 Attachment
anonymous
  • anonymous
When you have such multiplication of fractions, follow the rule : (Here N means numerator and D means denomination) N1 x N2 x N3 N1 x N2 x N3 -- -- -- = ------------- D1 D2 D3 D1 X D2 X D3
anonymous
  • anonymous
ohh ok
anonymous
  • anonymous
Now using this formula try to solve yourself and I'll check if it is correct
anonymous
  • anonymous
do u multiply the -7 with the N or D?
anonymous
  • anonymous
in the 2nd problem?
anonymous
  • anonymous
You can treat it as -7 -- 1 So you multiply -7 with the numerator group
anonymous
  • anonymous
oh okay
anonymous
  • anonymous
soo 98 -- -54
anonymous
  • anonymous
Correct!! But something more needs to be done
anonymous
  • anonymous
simplify? idk how to do that with this fraction
anonymous
  • anonymous
First, we hv to reduce it to lowest terms Second, make the denominator positive
anonymous
  • anonymous
OK, Both are even nos and hence divisible by 2 So go ahead and divide both by 2
anonymous
  • anonymous
Then multiply this by -1/-1 to make the denominator positive
anonymous
  • anonymous
Done????
anonymous
  • anonymous
49 -1 --- x ___ -27 -1
anonymous
  • anonymous
soo that means the answer is this? -49 --- 27
anonymous
  • anonymous
BINGO !!!! You got the hang of it !!
anonymous
  • anonymous
yay! is that simplest form?
anonymous
  • anonymous
Now I'll teach you how to reduce it to lower terms easily
anonymous
  • anonymous
okay :)
anonymous
  • anonymous
Yes it is because 49 is 7 x 7 and 27 is 3 x 3 x 3 So both numbers do not hv any common factor left
anonymous
  • anonymous
okay thank u
anonymous
  • anonymous
your question was 2 x -7 x -7 --- --- 9 -6
anonymous
  • anonymous
We modify it to 2 x -7 x -7 --- --- --- 9 1 - 6
anonymous
  • anonymous
Now we can easily see that 2 in the numerator of first fraction and 6 in the denominator of third fraction are both divisible by 2 and so we divide them by 2 to get 1 x -7 x -7 --- --- --- 9 1 -3
anonymous
  • anonymous
Following me???
anonymous
  • anonymous
ok now i have another ? is -3(3x-u)+(2u-4x) simplified to -9?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Now you can clearly see that numerators on top and denominators at bottom cannot be cross -cut as they do not have common factors so now multiply all numerators and all denominators and basically shift the - sign to the numerator
anonymous
  • anonymous
is that the simplified expression to that expression? yes.thank u for explaining that to me.
anonymous
  • anonymous
Yes, when u hv many fractions, you can use cross-cutting to cancel out common factors Now to yr second question..... -3(3x-u)+(2u-4x) = -9x + 3u + 2u - 4x = -9x - 4x + 3u + 2u = - 13x + 5u
anonymous
  • anonymous
How did u arrive at -9 ??
anonymous
  • anonymous
-3(-3x-u)+(2u-4x) -3(-3x)+1+(-4x) -3+1+-7
anonymous
  • anonymous
i did it wrong
anonymous
  • anonymous
but i was supposed to distribute
anonymous
  • anonymous
Yes, when you have an expression like -3(3x-u), you have to first use the DISTRIBUTIVE LAW to open the bracket and then solve further
anonymous
  • anonymous
wait..it said that wasn't correct.
anonymous
  • anonymous
What's the ans u hv????
anonymous
  • anonymous
i got 5x-1u
anonymous
  • anonymous
1u ? :|
anonymous
  • anonymous
-3(-3x-u) + (2u-4x) (9x-3u) + (2u-4x) -1u + 5x 5x + -1u 5x-1u
anonymous
  • anonymous
Then u gave me the wrong question the first time around!!!! Go and check....
anonymous
  • anonymous
i did! i'm sorry!! ahaha i put 3 and it was supposed to be -3 i think
anonymous
  • anonymous
but am i correct (with the problem i just did)
anonymous
  • anonymous
Well, one can always make mistakes while typing...... No, your answer is not correct. See my working below... -3(-3x-u) + (2u-4x) = 9x + 3u + 2u - 4x = 9x - 4x + 3u + 2u = 5x + 5u = 5 (x + u)
anonymous
  • anonymous
"5x-1u " :\ why is there a 1 in front of the u ?
anonymous
  • anonymous
you write "5-u" , no need for the 1 , it just makes it look messy , whenever I mark maths if I see anyone write coeffiecent of 1 then they lose marks
anonymous
  • anonymous
But her answer is wrong anyway.....
anonymous
  • anonymous
yeh , doesnt mean you cant correct notation
anonymous
  • anonymous
agreed :)
anonymous
  • anonymous
But if you deduct marks for this, I feel u r too harsh on the students. Just putting a circle and remarking shud do th job
anonymous
  • anonymous
yeah but for my learning purposes i sometimes put the -1 so i don't lose track.
anonymous
  • anonymous
but anyway..i see what u did harkirat ... idk what the crap i did! haha
anonymous
  • anonymous
No sweat, we all learn by making mistakes and correcting them
anonymous
  • anonymous
yeh, probably for like year4 kids in primary you wouldnt mark down , but if they are in high school and writting coefficents of 1 then there is something wrong , it makes you looks stupid putting 1u , because that shows the marker that you dont know that 1 times u =u
anonymous
  • anonymous
@elecengineer R u located in the US??
anonymous
  • anonymous
australia
anonymous
  • anonymous
R u an Indian by any chance??
anonymous
  • anonymous
no, not asian either
anonymous
  • anonymous
but alot of the electrical engineering lecturers at my uni are
anonymous
  • anonymous
im white lol
anonymous
  • anonymous
Just asking, hope u didn't mind
anonymous
  • anonymous
you shouldn't call students stupid...they mean the same thing. -1u and -u...just because it's marked differently doesnt mean you should mark down a grade..the answer is not wrong technically. its like your punishing your students because their teacher is a neat freak.
anonymous
  • anonymous
I'm an Indian and I know teachers here (in India) r very harsh with such things and penalise even small things
anonymous
  • anonymous
C'mon lauren, thats not nice
anonymous
  • anonymous
i dnt care what they say ^
anonymous
  • anonymous
but hey i'm just a first year college student. what do i know? but anywho the answer 5x+5u was correct!!! yayy!! i'm sorry. i'm just the type of person who says what i feel. i'm sorry if i offended you. just different opinions that is all.
anonymous
  • anonymous
but seriously, if you are in high school you shouldnt need to write the 1s
anonymous
  • anonymous
you are first year of uni , 19yrs old and you still write the 1s , you should have dropped that a long time ago lol
anonymous
  • anonymous
C'mon friends, let us change the topic
anonymous
  • anonymous
Do u need to ask anything else lauren??
anonymous
  • anonymous
agreed. i don't like negativity. and yes...one sec please.
anonymous
  • anonymous
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anonymous
  • anonymous
im not negative , just stating the facts, and I would be very surprised if a uni tutor doesnt mark down because of bad notation , its one thing to get the right answer, but you also need to express yourself confidently
anonymous
  • anonymous
if you click the link it makes it bigger.
anonymous
  • anonymous
^ thats first year uni math? cant be
anonymous
  • anonymous
what do you mean by "college"
anonymous
  • anonymous
i'm in Math098...i'm not the best math student and have never really been good at math or liked it...but it is a lower level of math.
anonymous
  • anonymous
but i do go to a university.
anonymous
  • anonymous
k... thats like the stuff we do in year8 in high school in australia
anonymous
  • anonymous
lauren, u do it and tell me the ans I'll confirm if it is ok This is a simple one, just b careful while using the Dist. LAW
anonymous
  • anonymous
i got -11y+8
anonymous
  • anonymous
wow :p
anonymous
  • anonymous
Bingo !! Its correct , the working as follows -4 (3y - 2) + y = -12y + 8 + y = - 11y + 8
anonymous
  • anonymous
=)
anonymous
  • anonymous
I should go fetch a really hard version of these from one of my high maths text books , these are far too easy :p
anonymous
  • anonymous
something much more complex
anonymous
  • anonymous
k u go do that. lol
anonymous
  • anonymous
Ok lauren, give this a try 2(x+ 3y) -7(2y - 5z) + 3(2x - 3y +z)
anonymous
  • anonymous
Focus and you'll do it right
anonymous
  • anonymous
k h/o
anonymous
  • anonymous
nah , just expanding is no fun, I am talking really messy algebraic fractions , with fractions inside fraction etc , really fun :p
anonymous
  • anonymous
C'mon elecengineer, giv her a break U r suggesting a mosquito weight fights Mike Tyson :D
anonymous
  • anonymous
8x-23y+38z
anonymous
  • anonymous
not quite
anonymous
  • anonymous
lauren, redo it and keep + and - signs in mind while expanding
anonymous
  • anonymous
it wasnt the signs that caused the mistake :|
anonymous
  • anonymous
8x-17y+38z and i missed one of the y terms while comining like terms.
anonymous
  • anonymous
combining*
anonymous
  • anonymous
Good, u did it!!
anonymous
  • anonymous
cool :)
anonymous
  • anonymous
Maths needs constant/regular/focussed practice
anonymous
  • anonymous
Find more such sums and keep doing them
anonymous
  • anonymous
thanks harkirat....are these like terms? 8x and 8x^2
anonymous
  • anonymous
no
anonymous
  • anonymous
do u know why??
anonymous
  • anonymous
bc of the exponent
anonymous
  • anonymous
Correct, In Algebra, for like terms we look at the variables and not the coefficient
anonymous
  • anonymous
For eg if u hv these four terms -5 x^2y^5z , 7x^2y^5 , 2zy^5x^2 , -11 xyz
anonymous
  • anonymous
k got it
anonymous
  • anonymous
The two like terms here are -5 x^2y^5z , 2zy^5x^2 becoz both hv x^2 y^5 and z as algebraic factors
anonymous
  • anonymous
Got it??
anonymous
  • anonymous
yep!
anonymous
  • anonymous
So just look at varible and their powers If two terms have all variables same and their powers same, then they r like, irrespective of their coefficients
anonymous
  • anonymous
here the operative word is ALL ALL variables same and their respective powers same

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