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anonymous
 5 years ago
2x1/6x1/5 please help!!
anonymous
 5 years ago
2x1/6x1/5 please help!!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the / is a division sign

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can u pls type it using the equation tab below. It is difficult to understand it like this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well h/o.. write ur answer as a fraction in simplest form. does this help? 2 X 1 X 1   6 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When you have such multiplication of fractions, follow the rule : (Here N means numerator and D means denomination) N1 x N2 x N3 N1 x N2 x N3    =  D1 D2 D3 D1 X D2 X D3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now using this formula try to solve yourself and I'll check if it is correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do u multiply the 7 with the N or D?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can treat it as 7  1 So you multiply 7 with the numerator group

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Correct!! But something more needs to be done

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0simplify? idk how to do that with this fraction

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First, we hv to reduce it to lowest terms Second, make the denominator positive

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, Both are even nos and hence divisible by 2 So go ahead and divide both by 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then multiply this by 1/1 to make the denominator positive

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.049 1  x ___ 27 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0soo that means the answer is this? 49  27

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0BINGO !!!! You got the hang of it !!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yay! is that simplest form?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now I'll teach you how to reduce it to lower terms easily

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes it is because 49 is 7 x 7 and 27 is 3 x 3 x 3 So both numbers do not hv any common factor left

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your question was 2 x 7 x 7   9 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We modify it to 2 x 7 x 7    9 1  6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now we can easily see that 2 in the numerator of first fraction and 6 in the denominator of third fraction are both divisible by 2 and so we divide them by 2 to get 1 x 7 x 7    9 1 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok now i have another ? is 3(3xu)+(2u4x) simplified to 9?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now you can clearly see that numerators on top and denominators at bottom cannot be cross cut as they do not have common factors so now multiply all numerators and all denominators and basically shift the  sign to the numerator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that the simplified expression to that expression? yes.thank u for explaining that to me.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, when u hv many fractions, you can use crosscutting to cancel out common factors Now to yr second question..... 3(3xu)+(2u4x) = 9x + 3u + 2u  4x = 9x  4x + 3u + 2u =  13x + 5u

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How did u arrive at 9 ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03(3xu)+(2u4x) 3(3x)+1+(4x) 3+1+7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i was supposed to distribute

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, when you have an expression like 3(3xu), you have to first use the DISTRIBUTIVE LAW to open the bracket and then solve further

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait..it said that wasn't correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What's the ans u hv????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03(3xu) + (2u4x) (9x3u) + (2u4x) 1u + 5x 5x + 1u 5x1u

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then u gave me the wrong question the first time around!!!! Go and check....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i did! i'm sorry!! ahaha i put 3 and it was supposed to be 3 i think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but am i correct (with the problem i just did)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, one can always make mistakes while typing...... No, your answer is not correct. See my working below... 3(3xu) + (2u4x) = 9x + 3u + 2u  4x = 9x  4x + 3u + 2u = 5x + 5u = 5 (x + u)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0"5x1u " :\ why is there a 1 in front of the u ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you write "5u" , no need for the 1 , it just makes it look messy , whenever I mark maths if I see anyone write coeffiecent of 1 then they lose marks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But her answer is wrong anyway.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh , doesnt mean you cant correct notation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But if you deduct marks for this, I feel u r too harsh on the students. Just putting a circle and remarking shud do th job

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah but for my learning purposes i sometimes put the 1 so i don't lose track.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but anyway..i see what u did harkirat ... idk what the crap i did! haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No sweat, we all learn by making mistakes and correcting them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh, probably for like year4 kids in primary you wouldnt mark down , but if they are in high school and writting coefficents of 1 then there is something wrong , it makes you looks stupid putting 1u , because that shows the marker that you dont know that 1 times u =u

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@elecengineer R u located in the US??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0R u an Indian by any chance??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but alot of the electrical engineering lecturers at my uni are

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just asking, hope u didn't mind

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you shouldn't call students stupid...they mean the same thing. 1u and u...just because it's marked differently doesnt mean you should mark down a grade..the answer is not wrong technically. its like your punishing your students because their teacher is a neat freak.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm an Indian and I know teachers here (in India) r very harsh with such things and penalise even small things

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0C'mon lauren, thats not nice

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dnt care what they say ^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but hey i'm just a first year college student. what do i know? but anywho the answer 5x+5u was correct!!! yayy!! i'm sorry. i'm just the type of person who says what i feel. i'm sorry if i offended you. just different opinions that is all.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but seriously, if you are in high school you shouldnt need to write the 1s

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are first year of uni , 19yrs old and you still write the 1s , you should have dropped that a long time ago lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0C'mon friends, let us change the topic

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do u need to ask anything else lauren??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0agreed. i don't like negativity. and yes...one sec please.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im not negative , just stating the facts, and I would be very surprised if a uni tutor doesnt mark down because of bad notation , its one thing to get the right answer, but you also need to express yourself confidently

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you click the link it makes it bigger.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0^ thats first year uni math? cant be

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you mean by "college"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm in Math098...i'm not the best math student and have never really been good at math or liked it...but it is a lower level of math.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i do go to a university.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k... thats like the stuff we do in year8 in high school in australia

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lauren, u do it and tell me the ans I'll confirm if it is ok This is a simple one, just b careful while using the Dist. LAW

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Bingo !! Its correct , the working as follows 4 (3y  2) + y = 12y + 8 + y =  11y + 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I should go fetch a really hard version of these from one of my high maths text books , these are far too easy :p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0something much more complex

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok lauren, give this a try 2(x+ 3y) 7(2y  5z) + 3(2x  3y +z)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Focus and you'll do it right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nah , just expanding is no fun, I am talking really messy algebraic fractions , with fractions inside fraction etc , really fun :p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0C'mon elecengineer, giv her a break U r suggesting a mosquito weight fights Mike Tyson :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lauren, redo it and keep + and  signs in mind while expanding

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it wasnt the signs that caused the mistake :

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.08x17y+38z and i missed one of the y terms while comining like terms.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Maths needs constant/regular/focussed practice

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find more such sums and keep doing them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks harkirat....are these like terms? 8x and 8x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Correct, In Algebra, for like terms we look at the variables and not the coefficient

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For eg if u hv these four terms 5 x^2y^5z , 7x^2y^5 , 2zy^5x^2 , 11 xyz

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The two like terms here are 5 x^2y^5z , 2zy^5x^2 becoz both hv x^2 y^5 and z as algebraic factors

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So just look at varible and their powers If two terms have all variables same and their powers same, then they r like, irrespective of their coefficients

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here the operative word is ALL ALL variables same and their respective powers same
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