anonymous
  • anonymous
Integral from 1 to 2 of ( v (e-e inverse) dv
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\int\limits_{1}^{2}v (e-e^-1)\]
anonymous
  • anonymous
easy
amistre64
  • amistre64
e is a constant; and so is 1/e

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More answers

anonymous
  • anonymous
2 ( e-e^-1 )
anonymous
  • anonymous
wait thats wrong lol
anonymous
  • anonymous
take the constant out
amistre64
  • amistre64
might as well ask what is the integral of 4v dv :)
anonymous
  • anonymous
integral v from 2 to 1
anonymous
  • anonymous
(1/2) [ 4-1] = 3/2 so \[\frac{3}{2} (e - e ^{-1})\]
anonymous
  • anonymous
^ answer
amistre64
  • amistre64
\[F(v)=\frac{v^2(e-e^{-1})}{2} |_{1}^{2}\]
amistre64
  • amistre64
e - (1/e) = (e^2 - 1)/e right?
anonymous
  • anonymous
So don't treat v as a constant
anonymous
  • anonymous
its dv on the end
amistre64
  • amistre64
v is the variable here
anonymous
  • anonymous
Ok
anonymous
  • anonymous
So which answer is correct
amistre64
  • amistre64
4.7008047745751485263396882938069 -1.1752011936437871315849220734517 -------------------------------------- 3.525603580931361394754766220355 is what i get :)
anonymous
  • anonymous
:|
amistre64
  • amistre64
F(2) - F(1)
anonymous
  • anonymous
stuff like that is what puts people off maths ^ :|
anonymous
  • anonymous
no one cares about the numbers, especially to 20 decimal places , the final number doesnt matter , its how you go the number that matters Whenever you have e's or \[\pi\] in the answer then the answer should be given as exact value
anonymous
  • anonymous
are you in kindergarten amistre lol
amistre64
  • amistre64
i gave the exact and the approximate; or so i thought....
amistre64
  • amistre64
i even gave a reason of "how" it is obtained.... right?
anonymous
  • anonymous
your like the guys that memorise pi to 1000's of demical places
amistre64
  • amistre64
lol.... 7 digits on pi :) e = 2.71828182845905... is that best i got with that one :)
anonymous
  • anonymous
never give an answer to 20decimal places, makes you lokok like an idiot, 2 ( maybe 3 ) max , no one cares bout the rest. When a person that is new to maths sees something really long and unneccessary like that it is sure to put them off
anonymous
  • anonymous
*look like .....
amistre64
  • amistre64
i dont have to include decimals to look like an idiot; im a pro at that regardless :) and i figured that if they are asking calculus questions then they arent all that new to math...

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