anonymous
  • anonymous
use the exact method to solve the DE: 2xydx + x^2ydy=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Are you confused as to how it's done? Just wanting to check your answer or what?
anonymous
  • anonymous
i checked for exactness and it wasn't exact so I used the next method to check for exactness and it looks as thought I got something but unsure
anonymous
  • anonymous
It doesn't look exact to me because the term on the left has an extra y in it.

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anonymous
  • anonymous
using the test for exactness it doesnt come out exact but when you use integrating factors to solve then it works
anonymous
  • anonymous
its not an exact diff equation. divide throughout by x^2y and reduce it to separable form and solve it. its easy
anonymous
  • anonymous
if i used integrating factor method i was tuahgt to do if it doesnt come out exact then i get the integrating factor of e^(y-ln(y))
anonymous
  • anonymous
how did u check the exactness?
anonymous
  • anonymous
partial derivative of M with respect to y and partial derivative of N with respect to x and see if they are equal
anonymous
  • anonymous
P(x,y)=2xy Q(x,y)=x^2y for exactness partial derivative of p w.r.ty=partial derivative of Q w.r.t x
anonymous
  • anonymous
there is a method uzma ,differentiate the term with dx with respect to y and the term with dy with respect to x ,if both differentiated terms become equal then they r exact,otherwise non exact
anonymous
  • anonymous
yes right :)
anonymous
  • anonymous
com for chat uzma
anonymous
  • anonymous
so what do u guess about the exactness?
anonymous
  • anonymous
when doing that they come out non exact and then there is a method to use after that where you use integrating factors after applying an equation and then go from there
anonymous
  • anonymous
not exact initially
anonymous
  • anonymous
any help??
anonymous
  • anonymous
the eq is exact
anonymous
  • anonymous
non exact...m sorry :)
anonymous
  • anonymous
so the eq can made by multiplying with intgrating factor

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