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anonymous
 5 years ago
use the exact method to solve the DE:
2xydx + x^2ydy=0
anonymous
 5 years ago
use the exact method to solve the DE: 2xydx + x^2ydy=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you confused as to how it's done? Just wanting to check your answer or what?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i checked for exactness and it wasn't exact so I used the next method to check for exactness and it looks as thought I got something but unsure

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It doesn't look exact to me because the term on the left has an extra y in it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0using the test for exactness it doesnt come out exact but when you use integrating factors to solve then it works

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its not an exact diff equation. divide throughout by x^2y and reduce it to separable form and solve it. its easy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if i used integrating factor method i was tuahgt to do if it doesnt come out exact then i get the integrating factor of e^(yln(y))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did u check the exactness?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0partial derivative of M with respect to y and partial derivative of N with respect to x and see if they are equal

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0P(x,y)=2xy Q(x,y)=x^2y for exactness partial derivative of p w.r.ty=partial derivative of Q w.r.t x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is a method uzma ,differentiate the term with dx with respect to y and the term with dy with respect to x ,if both differentiated terms become equal then they r exact,otherwise non exact

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what do u guess about the exactness?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when doing that they come out non exact and then there is a method to use after that where you use integrating factors after applying an equation and then go from there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0non exact...m sorry :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the eq can made by multiplying with intgrating factor
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