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anonymous
 5 years ago
use method of exactness to solve the DE:
(e^xsiny2ysinx)dx+(e^xcosy +2cosx)dy=0
anonymous
 5 years ago
use method of exactness to solve the DE: (e^xsiny2ysinx)dx+(e^xcosy +2cosx)dy=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the eq is exact as partial derivative of P(x,y) w.r.t y=partial derivative of Q(x,y) w.r.t x R(x,y)=int( e^xsiny2ysinx)dx =e^xsiny+2ycosx +h(y) partial derivative of R w.r.t y=e^xcosy+2cosx+h'(y) = Q(x,y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which shows that h'(y)=0
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