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anonymous

  • 5 years ago

can i ask a physics question pls .......

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  1. anonymous
    • 5 years ago
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    no!

  2. anonymous
    • 5 years ago
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    :p

  3. anonymous
    • 5 years ago
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    y

  4. anonymous
    • 5 years ago
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    i have urgent problem

  5. anonymous
    • 5 years ago
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    u can ask,but no guarantee for the solution :)

  6. anonymous
    • 5 years ago
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    my question is: If the momentum of a moving object is increased by 100%. Than the Kinetic energy of that object will be increased by :

  7. anonymous
    • 5 years ago
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    p = mv = momentum

  8. anonymous
    • 5 years ago
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    K = kinetic energy = (1/2)mv^2

  9. anonymous
    • 5 years ago
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    if we double momentum, that means instead of p = mv , we have p=2mv

  10. anonymous
    • 5 years ago
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    now , p = 2K/ v

  11. anonymous
    • 5 years ago
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    so K = pv/2

  12. anonymous
    • 5 years ago
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    wait, think I went round in a circle :|

  13. anonymous
    • 5 years ago
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    but its just playing with equations, and ratios

  14. anonymous
    • 5 years ago
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    KE = 1/2* mv^2 = 1/2* p* v

  15. anonymous
    • 5 years ago
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    I think we can safely assume that all the in increase in momentum is due to velocity, not a change in mass

  16. anonymous
    • 5 years ago
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    that makes it much easier

  17. anonymous
    • 5 years ago
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    i guess kinetic energy would be doubled

  18. anonymous
    • 5 years ago
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    so we essentially double our velocity

  19. anonymous
    • 5 years ago
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    which quadruples our kinetic energy

  20. anonymous
    • 5 years ago
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    we square velocity in the equation

  21. anonymous
    • 5 years ago
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    ie times by 4

  22. anonymous
    • 5 years ago
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    bad explaination Kinetic energy of object mass m, velocity v: = (1/2) m v^2 Kinetic energy of object mass m , velocity 2v : = (1/2) m (2v)^2 = (1/2) m v^2 (4) = 4K

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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