anonymous
  • anonymous
solve the DE using the exact method: y^2dx - x^2dy=0
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
how about the solution of the problems u posted earlier?u got it?
anonymous
  • anonymous
p(x,y)=y^2 Q(x,y)=-x^2
anonymous
  • anonymous
yeh got them

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anonymous
  • anonymous
these arent exact......they are spearable but it says to solve using exact method
anonymous
  • anonymous
but they can be made exact if we multiply the eq with integarting factor
anonymous
  • anonymous
again the given eq is not exact :)
anonymous
  • anonymous
yeh but u cant get the integrating factor to be of one variable so that method wont work
anonymous
  • anonymous
yea right
anonymous
  • anonymous
so its impossible to solve using the exact methods
anonymous
  • anonymous
ok lets find the integrating factor
anonymous
  • anonymous
http://www.sosmath.com/diffeq/first/intfactor/intfactor.html
anonymous
  • anonymous
oh we cant find an integrating factor, darn
anonymous
  • anonymous
so use seperable equations , i get dx/x^2 = dy/y^2

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