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anonymous

  • 5 years ago

solve the DE using the exact method: y^2dx - x^2dy=0

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  1. anonymous
    • 5 years ago
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    how about the solution of the problems u posted earlier?u got it?

  2. anonymous
    • 5 years ago
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    p(x,y)=y^2 Q(x,y)=-x^2

  3. anonymous
    • 5 years ago
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    yeh got them

  4. anonymous
    • 5 years ago
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    these arent exact......they are spearable but it says to solve using exact method

  5. anonymous
    • 5 years ago
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    but they can be made exact if we multiply the eq with integarting factor

  6. anonymous
    • 5 years ago
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    again the given eq is not exact :)

  7. anonymous
    • 5 years ago
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    yeh but u cant get the integrating factor to be of one variable so that method wont work

  8. anonymous
    • 5 years ago
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    yea right

  9. anonymous
    • 5 years ago
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    so its impossible to solve using the exact methods

  10. anonymous
    • 5 years ago
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    ok lets find the integrating factor

  11. anonymous
    • 5 years ago
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    http://www.sosmath.com/diffeq/first/intfactor/intfactor.html

  12. anonymous
    • 5 years ago
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    oh we cant find an integrating factor, darn

  13. anonymous
    • 5 years ago
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    so use seperable equations , i get dx/x^2 = dy/y^2

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spraguer (Moderator)
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