cn someone give me a website with a free online tutor

- anonymous

cn someone give me a website with a free online tutor

- Stacey Warren - Expert brainly.com

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- jamiebookeater

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- anonymous

Open study

- anonymous

open study? thts the name of the site

- anonymous

Yes, there are 27 people available right now that may be able to help you. Just post your question.

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## More answers

- anonymous

ok\[x/3=30\]

- anonymous

90

- anonymous

Multiply both sides by 3.

- anonymous

which maths paper?

- anonymous

x/3=30
(3) x/3=30(3)
x=90

- anonymous

thank you

- anonymous

can i go through this study guide with yall because its been a long time since i did any of this

- anonymous

If you want :)

- anonymous

\[5x-2=x-9\]

- anonymous

5x-2=x-9
4x=-7
x=-7/4

- anonymous

ok thank! can i send a picture of the next problem

- anonymous

##### 1 Attachment

- radar

Is the circumference 3.4 meters?

- radar

Is that the diameter of 3.4 meters

- anonymous

the is question is what is the circumfrence and area of the circle

- radar

The image is pretty fuzzy. If the diameter is 3.4 meters the circumference is Pi times 3.4. Or 10.68 meters

- anonymous

:D this is so so much help!
should i send a better pic

- radar

O.K, if that is the diameter (3.4), what would be the radius?

- radar

Area of a circle is:\[A=\pi \times r ^{2}\]
where r equals the radius.

- anonymous

would tht be half of tht 3.4

- radar

yes, radius is one half the diameter.

- radar

I get 1.7 for the radius. What did you come up with?

- anonymous

im checking now! :)

- anonymous

got the same

- radar

Good, use that value for r in the equation for area of a circle (6 post up from this one)

- radar

\[A=\pi \times (1.7)^{2}\]

- anonymous

this will give the answer

- radar

Yes, what did you come up with?

- radar

I got 9 sq

- radar

I got 9 sq meters.

- radar

Did you get something like that?

- anonymous

yes!!!

- radar

Good have a nice day.

- anonymous

thank you

- anonymous

i need help with this next problem! any takers?

- radar

I can help you (maybe) for one more before I have to leave. I don't mind helping those who are willing to help themselves.

- anonymous

find missing x

##### 1 Attachment

- radar

The image is really fuzzy. It appears there is a line y=3x-7 and then there appears to be another line intersecting whose equation is y=5x+11. Is this what you see?

- anonymous

the top of the intersecting line is 5-x=11

- anonymous

youre right srry

- radar

O.K. then we could say at that point where they are intersect y=y
5x-11+3x-7
2x=4
x=2
You could plus that in and solve the y point by inspection I can see that y=-1

- radar

Wait in minute, did you say it is 5x+11, not 5x-11??

- anonymous

yeah its 5x+11

- anonymous

it looks to me like a geometry question:
5x+11 + 3x-7 = 180

- radar

Then it would be 5x+11=3x-7
2x=-18
x=-9

- anonymous

From the picture it looks like we have a linear pair (a set of angles that make a straight line) so if we add the angles together we get 180 degrees. Setting them equal gives 5x+11 + 3x-7 = 180 so 8x+4=180.
8x = 176
x = 22 degrees

- radar

Could be, to me it looked like two intersecting lines, all be it one rotated to align it self with the x axis, and the intersection point was to be solved.

- anonymous

ok so they way tbates did it or the way you did?

- anonymous

I can see that too, but the cursive l beside the line leads me to think its a linear pairs

- radar

It appears that Tbates has said this was a geometry question, he is probably rights, as theother questions were about circles etc. so I leave you in his capable hands lol

- anonymous

If it were lines on a graph I would have wholeheartedly agreed with your solution radar.

- radar

Yes, I don't see any coordinates etc. I told christy_white, "maybe" I could help her, in this case maybe not. However, christy, is wanting assistance and appears to be sincerely trying, if you can help, please do.

- anonymous

I'll be around for a bit so post the questions away!

- anonymous

thanks guys ")

- anonymous

next question?

- anonymous

Fire away!

- radar

Go aheaD Tbates will be back

- anonymous

ok sending the picture

- anonymous

if each quadirlateral is a parallelgram then find the value of x y z

##### 1 Attachment

- anonymous

tht two problems

- anonymous

tht two problems

- anonymous

If we look at 7 first and specifically z. Again we have a linear pair so:
z + 78 = 180

- anonymous

This means z = 102 in the first problem.

- anonymous

for x we have a set of parallel lines cut by a transversal so x = 24 (alternate interior angles) http://www.mathsisfun.com/geometry/alternate-interior-angles.html

- anonymous

Finally all interior angles of a triangle add to 180 so:
y + x + 78 = 180
y + 24 + 78 = 180
y + 102 = 180
y = 78

- anonymous

ok i gotcha!

- anonymous

On the second one there's a theorem that states opposite angles in a parallelogram are equal so z = 104.
Using alternate interior angles x = 32 and y = 44

- anonymous

Does that make sense?

- anonymous

had to take my dog out for a min. but im looking over it now

- anonymous

yeah i understand

- anonymous

Excellent! Have any more questions?

- anonymous

ohhh yes i have a whole study guide lol! i can take as much help as anyone is willing to give

- anonymous

I'll be around, I'm also answering other questions but I'll be helping you out as well.

- anonymous

the distance btw two points\[( 2, 5)(6, -1)\]

- anonymous

There is a formula for finding the distance between two points and it's:
\[distance = \sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1})^{2}}\]
\[\sqrt{(5-2)^{2}+(-1-6)^{2}}\]
\[\sqrt{(3)^{2}+(-7)^{2}}\]
\[\sqrt{9 + 47}\]
√56 = 7.48

- anonymous

oops I meant √58 = 7.62

- anonymous

all done?

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