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  • 5 years ago

how to integrate xe^(-x^2), the upper bound is infinity, lower bound is zero? I stuck on -1/2 lim b going to infinity e^b -1. e^b-1 is going to infinity, how to do I evaluate this

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  1. anonymous
    • 5 years ago
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    If I understand your problem correctly, that is the answer. Looks like you integrated correctly, but now you are asked to evaluate it from infinity to 0. What you are examining here is what happens as you approach infinity. You must take the limit of the integral \[\lim_{t \rightarrow \infty}\int\limits_{0}^{t} \] Treat it like a limit problem and I we see that as t approaches infinity the value also approaches infinity

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