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anonymous

  • 5 years ago

integral from 0 to 1 of cos(arcsinx)

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  1. anonymous
    • 5 years ago
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    Let \[\theta =\sin^{-1} x\]

  2. anonymous
    • 5 years ago
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    Therefore \[x/1=\sin \theta =opp/hyp\]Draw my triangle x is opp, 1 hyp, sq rt (1-x^2) adj

  3. anonymous
    • 5 years ago
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    From that triangle you have info to find cos theta which you would integrate

  4. anonymous
    • 5 years ago
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    do you integrate cos theta or cos (sqrt(1-x^2)) ?

  5. anonymous
    • 5 years ago
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    cos theta in and of itself does not contain the info in your problem. However cos theta (which essentially is your problem) is equal to sq root (1-x^2) which contains all relevant info. So integrate sq rt (1-x^2).

  6. anonymous
    • 5 years ago
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    how do you integrate sq rt(1-x^2)?

  7. anonymous
    • 5 years ago
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    You have to find relevant trig sub.

  8. anonymous
    • 5 years ago
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    Your instructor gives very interesting problems. What school? what course?

  9. anonymous
    • 5 years ago
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    University of Miami: Calculus II

  10. anonymous
    • 5 years ago
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    Go 'Canes

  11. anonymous
    • 5 years ago
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    Lol! Thanks

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