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anonymous
 5 years ago
what is the solution in interval notation? 5/3x le 10
anonymous
 5 years ago
what is the solution in interval notation? 5/3x le 10

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05/3x≤10 multiply each side by 3/5 (don't forget to switch the sign!) x≥6 in interval notation [6, infty)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its 5 over 3 x \[\le\] 10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do i write it in interval notation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05/3x ≤ 10 3x ≤ 1/2 x ≤ 1/6 which is to say that x is an element of (epsilon) (0,1/6] (parentheses because you can't have x=0, and a bracket because the expression equals 10 if x = 1/6). TBates, if you plug in 6, or anything greater, into the original inequality you don't even come close to approaching 10. In your method, you forgot that x is in the denominator  not the numerator. If you graph 5/3x, you have a rational expression with asymptotes. You can use that to find the values at which the function is less than 10: in this circumstance, any value between 0 and 1/6 gives 10 or less. Anything less than 0 gives a value higher than 10, and it certainly cannot equal zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but that answer is still correct...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Quantum you forgot that the problem had 3 in the denominator, the answer I gave previously is correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How it was written the x is not in parenthesis and therefor not a part of the denominator.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So it was 5/3 * x? If so, then yeah, you're right. I thought it was 5/(3x).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, that was my fault. it was hard to write it on here and show the 3 was not part of the x
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