anonymous
  • anonymous
what is the solution in interval notation? -5/3x le -10
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
-5/3x≤-10 multiply each side by -3/5 (don't forget to switch the sign!) x≥6 in interval notation [6, infty)
anonymous
  • anonymous
its -5 over 3 x \[\le\] -10
anonymous
  • anonymous
how do i write it in interval notation?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ooooh got it.
anonymous
  • anonymous
with 6,infinitie)
anonymous
  • anonymous
\[[6, \infty)\]
anonymous
  • anonymous
thank u
anonymous
  • anonymous
-5/3x ≤ -10 3x ≤ 1/2 x ≤ 1/6 which is to say that x is an element of (epsilon) (0,1/6] (parentheses because you can't have x=0, and a bracket because the expression equals -10 if x = 1/6). TBates, if you plug in 6, or anything greater, into the original inequality you don't even come close to approaching -10. In your method, you forgot that x is in the denominator -- not the numerator. If you graph -5/3x, you have a rational expression with asymptotes. You can use that to find the values at which the function is less than -10: in this circumstance, any value between 0 and 1/6 gives -10 or less. Anything less than 0 gives a value higher than -10, and it certainly cannot equal zero.
anonymous
  • anonymous
but that answer is still correct...
anonymous
  • anonymous
Quantum you forgot that the problem had 3 in the denominator, the answer I gave previously is correct.
anonymous
  • anonymous
How it was written the x is not in parenthesis and therefor not a part of the denominator.
anonymous
  • anonymous
So it was 5/3 * x? If so, then yeah, you're right. I thought it was 5/(3x).
anonymous
  • anonymous
sorry, that was my fault. it was hard to write it on here and show the 3 was not part of the x

Looking for something else?

Not the answer you are looking for? Search for more explanations.