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anonymous

  • 5 years ago

last problem, i swear *x+6*-*x-5*=1 The stars mean its in a radical

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  1. anonymous
    • 5 years ago
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    \[\sqrt{x+6}-\sqrt{x-5}=1\]

  2. anonymous
    • 5 years ago
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    yes thats it

  3. anonymous
    • 5 years ago
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    The answer is x = 30 (I knew 30+6 is 36 and the square root of that is 6 and 30-5 is 25 and the square root of that is 5 so 6-5 = 1)

  4. anonymous
    • 5 years ago
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    how did you get that

  5. anonymous
    • 5 years ago
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    I used guess and check on this one :P. but give me a moment and I may be able to figure out how to go through the steps to prove it.

  6. anonymous
    • 5 years ago
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    Sigh. This one takes a little while to type out in LaTex :P Hold on..

  7. anonymous
    • 5 years ago
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    sqrt ( x+6) = 1 + sqrt (x+5)

  8. anonymous
    • 5 years ago
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    square both sides

  9. anonymous
    • 5 years ago
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    x+6 = 1 + 2 sqrt (x+5) + (x+5)

  10. anonymous
    • 5 years ago
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    x+6 - 1 - (x+5) = 2 sqrt (x+5)

  11. anonymous
    • 5 years ago
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    err

  12. anonymous
    • 5 years ago
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    sqrt ( x+6) = 1 + sqrt (x- 5)

  13. anonymous
    • 5 years ago
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    x+6 = 1 + 2 sqrt ( x - 5) + x- 5 , when you square both sides

  14. anonymous
    • 5 years ago
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    6 + 5-1 = 2 sqrt ( x - 5)

  15. anonymous
    • 5 years ago
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    10 / 2 = sqrt (x-5)

  16. anonymous
    • 5 years ago
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    25 = x - 5 , x = 30

  17. anonymous
    • 5 years ago
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    THIS IS A JOKE

  18. anonymous
    • 5 years ago
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    anwar, we are trying to do the proof

  19. anonymous
    • 5 years ago
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    in my post

  20. anonymous
    • 5 years ago
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    thanks for the help cantor, I was looking at conjugates for some reason

  21. anonymous
    • 5 years ago
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    \[\sqrt{x+6} - \sqrt{x-5} = 1\] \[\sqrt{x-5} = \sqrt{x-6} - 1\] squaring both sides \[x - 5 = x - 2\sqrt{x+6} - 7\]\[2\sqrt{x+6} = 12\]\[\implies x = 30\]

  22. anonymous
    • 5 years ago
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    Sorry, third line should have a +7.

  23. anonymous
    • 5 years ago
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    how are you a champion?

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spraguer (Moderator)
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