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anonymous

  • 5 years ago

Asa, Bill, Cathy, Dino, and Eve are randomly seated in a row of 5 seats. Find the probability that Asa will sit next to Bill.

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  1. anonymous
    • 5 years ago
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    View asa and bill as one person. Then, find the number of ways the four "people" can fill the seats. Then view bill and asa as one person, and do it again. Sum the two. Thats the total number of ways bill and asa can sit next to each other. Now, find the total number of ways the five students can sit in the row. The probability they sit next to each other is the the number of ways they can sit next to each other divided by the number of ways they can sit overall.

  2. anonymous
    • 5 years ago
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    Note that order is important!

  3. anonymous
    • 5 years ago
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    can u show the work?? lol

  4. anonymous
    • 5 years ago
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    Can you?

  5. anonymous
    • 5 years ago
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    9 / 5!

  6. anonymous
    • 5 years ago
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    8 / 5!

  7. anonymous
    • 5 years ago
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    what? It's supposed to be a fraction

  8. anonymous
    • 5 years ago
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    you have ABCDE , there are 5! ways of sitting them. that will be your denominator

  9. anonymous
    • 5 years ago
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    the favorable is AB sitting together, you can have oh...

  10. anonymous
    • 5 years ago
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    you can have AB, BA , and there are 4 places , so 4* 2

  11. anonymous
    • 5 years ago
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    thats your numerator

  12. anonymous
    • 5 years ago
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    what's the numerator?

  13. anonymous
    • 5 years ago
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    8

  14. anonymous
    • 5 years ago
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    so you have 8/120

  15. anonymous
    • 5 years ago
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    that's not a choice though (1) 1/60 (2) 2/5 (3) 1/10 (4) 4/15

  16. anonymous
    • 5 years ago
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    oh

  17. anonymous
    • 5 years ago
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    ok there are 2x4x3! in the numerator

  18. anonymous
    • 5 years ago
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    so 2/5

  19. anonymous
    • 5 years ago
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    wait 24/120 is 1/5 not 2/5

  20. anonymous
    • 5 years ago
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    no thats 48/120

  21. anonymous
    • 5 years ago
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    oh, I got u

  22. anonymous
    • 5 years ago
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    2x4x3! = 2x4x(3x2x1)

  23. anonymous
    • 5 years ago
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    give me medal NOW

  24. anonymous
    • 5 years ago
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    I got 2/5.

  25. anonymous
    • 5 years ago
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    me too

  26. anonymous
    • 5 years ago
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    there are 2 ways for AB to sit next to each other, they can move around in 4 different places, then there are 3! for the rest of the other people to sit

  27. anonymous
    • 5 years ago
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    wait so basically it's 5!/ 2!4! ???

  28. anonymous
    • 5 years ago
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    shut up omg. Look at the method i proposed. 2(4!)/(5!)

  29. anonymous
    • 5 years ago
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    well you treat AB as K, so you have K C D E , and how many ways can you reararnge that

  30. anonymous
    • 5 years ago
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    then K has 2! ways

  31. anonymous
    • 5 years ago
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    shut up, omg, GROW UP

  32. anonymous
    • 5 years ago
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    u 2 r arguing?

  33. anonymous
    • 5 years ago
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    so you have K C D E , where K is AB, and you have 4! ways of rearranging that, but K is actually AB or BA, so 4! * 2!

  34. anonymous
    • 5 years ago
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    azn, can you give me medal, i got answer first

  35. anonymous
    • 5 years ago
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    can u guys explain what u did?

  36. anonymous
    • 5 years ago
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    i did

  37. anonymous
    • 5 years ago
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    explain then right now

  38. anonymous
    • 5 years ago
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    treat AB as K, since they always sit next to each other, so you have K C D E , correct ?

  39. anonymous
    • 5 years ago
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    yea

  40. anonymous
    • 5 years ago
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    so how many ways to rearrange K C D E ?

  41. anonymous
    • 5 years ago
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    24

  42. anonymous
    • 5 years ago
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    right, but for each one of those arrangements, you have AB or BA

  43. anonymous
    • 5 years ago
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    since they can swap

  44. anonymous
    • 5 years ago
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    so you need 24 x 2

  45. anonymous
    • 5 years ago
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    in other words, K can be AB or K can be BA

  46. anonymous
    • 5 years ago
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    so you have 24 with AB , and 24 with BA, so 24 + 24

  47. anonymous
    • 5 years ago
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    ok and how did u get the 5! part

  48. anonymous
    • 5 years ago
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    thats the number of ways to rearrange A B C D E

  49. anonymous
    • 5 years ago
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    5 !

  50. anonymous
    • 5 years ago
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    wheres my medal

  51. anonymous
    • 5 years ago
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    PLEASSSSSSSSEEEEEEEEEEEEEEEEEEEEEEEEE

  52. anonymous
    • 5 years ago
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    oh I got it

  53. anonymous
    • 5 years ago
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    how do I give u a medal? It's my first time here, how?

  54. anonymous
    • 5 years ago
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    next to my name

  55. anonymous
    • 5 years ago
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    it should say give medal

  56. anonymous
    • 5 years ago
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    it doesn't

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