anonymous
  • anonymous
Asa, Bill, Cathy, Dino, and Eve are randomly seated in a row of 5 seats. Find the probability that Asa will sit next to Bill.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
View asa and bill as one person. Then, find the number of ways the four "people" can fill the seats. Then view bill and asa as one person, and do it again. Sum the two. Thats the total number of ways bill and asa can sit next to each other. Now, find the total number of ways the five students can sit in the row. The probability they sit next to each other is the the number of ways they can sit next to each other divided by the number of ways they can sit overall.
anonymous
  • anonymous
Note that order is important!
anonymous
  • anonymous
can u show the work?? lol

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anonymous
  • anonymous
Can you?
anonymous
  • anonymous
9 / 5!
anonymous
  • anonymous
8 / 5!
anonymous
  • anonymous
what? It's supposed to be a fraction
anonymous
  • anonymous
you have ABCDE , there are 5! ways of sitting them. that will be your denominator
anonymous
  • anonymous
the favorable is AB sitting together, you can have oh...
anonymous
  • anonymous
you can have AB, BA , and there are 4 places , so 4* 2
anonymous
  • anonymous
thats your numerator
anonymous
  • anonymous
what's the numerator?
anonymous
  • anonymous
8
anonymous
  • anonymous
so you have 8/120
anonymous
  • anonymous
that's not a choice though (1) 1/60 (2) 2/5 (3) 1/10 (4) 4/15
anonymous
  • anonymous
oh
anonymous
  • anonymous
ok there are 2x4x3! in the numerator
anonymous
  • anonymous
so 2/5
anonymous
  • anonymous
wait 24/120 is 1/5 not 2/5
anonymous
  • anonymous
no thats 48/120
anonymous
  • anonymous
oh, I got u
anonymous
  • anonymous
2x4x3! = 2x4x(3x2x1)
anonymous
  • anonymous
give me medal NOW
anonymous
  • anonymous
I got 2/5.
anonymous
  • anonymous
me too
anonymous
  • anonymous
there are 2 ways for AB to sit next to each other, they can move around in 4 different places, then there are 3! for the rest of the other people to sit
anonymous
  • anonymous
wait so basically it's 5!/ 2!4! ???
anonymous
  • anonymous
shut up omg. Look at the method i proposed. 2(4!)/(5!)
anonymous
  • anonymous
well you treat AB as K, so you have K C D E , and how many ways can you reararnge that
anonymous
  • anonymous
then K has 2! ways
anonymous
  • anonymous
shut up, omg, GROW UP
anonymous
  • anonymous
u 2 r arguing?
anonymous
  • anonymous
so you have K C D E , where K is AB, and you have 4! ways of rearranging that, but K is actually AB or BA, so 4! * 2!
anonymous
  • anonymous
azn, can you give me medal, i got answer first
anonymous
  • anonymous
can u guys explain what u did?
anonymous
  • anonymous
i did
anonymous
  • anonymous
explain then right now
anonymous
  • anonymous
treat AB as K, since they always sit next to each other, so you have K C D E , correct ?
anonymous
  • anonymous
yea
anonymous
  • anonymous
so how many ways to rearrange K C D E ?
anonymous
  • anonymous
24
anonymous
  • anonymous
right, but for each one of those arrangements, you have AB or BA
anonymous
  • anonymous
since they can swap
anonymous
  • anonymous
so you need 24 x 2
anonymous
  • anonymous
in other words, K can be AB or K can be BA
anonymous
  • anonymous
so you have 24 with AB , and 24 with BA, so 24 + 24
anonymous
  • anonymous
ok and how did u get the 5! part
anonymous
  • anonymous
thats the number of ways to rearrange A B C D E
anonymous
  • anonymous
5 !
anonymous
  • anonymous
wheres my medal
anonymous
  • anonymous
PLEASSSSSSSSEEEEEEEEEEEEEEEEEEEEEEEEE
anonymous
  • anonymous
oh I got it
anonymous
  • anonymous
how do I give u a medal? It's my first time here, how?
anonymous
  • anonymous
next to my name
anonymous
  • anonymous
it should say give medal
anonymous
  • anonymous
it doesn't

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