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anonymous

  • 5 years ago

How do I find the answer to a cubed + 27t cubed by factoring

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  1. amistre64
    • 5 years ago
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    a^3 +27t , is that the question?

  2. anonymous
    • 5 years ago
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    There is a theorem on how to factor cubics. (a - b)(a + 2ab + b) I think?

  3. amistre64
    • 5 years ago
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    27t^3; and davis is correct :)

  4. anonymous
    • 5 years ago
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    Sorry thats backwards. \[(a+b)(a^2 - 2ab + b^2)\]

  5. amistre64
    • 5 years ago
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    lol..... semantics :)

  6. anonymous
    • 5 years ago
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    a = a, b = 27t

  7. anonymous
    • 5 years ago
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    Sorry first time using this site...not sure how to enter the problems

  8. anonymous
    • 5 years ago
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    Sorry its still wrong, \[(a + b)(a^2 - ab + b^2)\]

  9. amistre64
    • 5 years ago
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    enter them the best you can and clarify as needed really :)

  10. amistre64
    • 5 years ago
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    (a^3 +- b^3) (a +- b)(a^2 -+ ab + b^2)

  11. anonymous
    • 5 years ago
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    Thank you..ok so which one am I to use? The question is a to the third power or cubed + 27t to the third power or cubed

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