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anonymous
 5 years ago
find the equation of the line that passes through P (2,2,3) and is paralel to the line 3(x2)=2(y2)=6(z+3)?
anonymous
 5 years ago
find the equation of the line that passes through P (2,2,3) and is paralel to the line 3(x2)=2(y2)=6(z+3)?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0are those equa;l signs spoose to be (+) signs?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the normal vector appeart to be <3,2,6> assuming those are sposed to be (+) signs

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the equation appears to be: 3x6 +2y4 +6z+18 = 0 3x + 2y +6z +8 = 0 would be the eqaution of the plane

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i wrote it as it is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that isn't in the answer choices

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what are the answer choices :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok give me a secon it's kind of a lot to type out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its looks line parametric representation of the line... what is the topic of your study?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a) x=2+2t, y=2+3t, z=3+t b)x=2+3t, y=2+2t, z=3+6t c)x=2+2t, y=23t, z=3t d)x=2+3t, y=22t, z=36t

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is cal 3...can you help?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a) x=2+2t, y=2+3t, z=3+t b)x=2+3t, y=2+2t, z=3+6t c)x=2+2t, y=23t, z=3t d)x=2+3t, y=22t, z=36t my guess is (b) but i have no proof to back that up......its been awhile :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thanks for looking

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0To find the parametric equations of the line passing through the point (2,2,3) and parallel to the vector <3,2,6>. We first find the vector equation of the line. Here, r_0=<2,2,3> and v=<3,2,6>. Thus, the line has vector equation r=<2,2,3>+t<3,2,6>. The parametric equations of the line are: x=2+3t, y=2+2t, and z=3+6t. [B]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0copied that off the web and included your numbers :) http://www.math.oregonstate.edu/home/programs/undergrad/CalculusQuestStudyGuides/vcalc/lineplane/lineplane.html
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