Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

find the equation of the line that passes through P (2,2,-3) and is paralel to the line 3(x-2)=2(y-2)=6(z+3)?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

- katieb

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- amistre64

are those equa;l signs spoose to be (+) signs?

- amistre64

the normal vector appeart to be <3,2,6> assuming those are sposed to be (+) signs

- amistre64

the equation appears to be:
3x-6 +2y-4 +6z+18 = 0
3x + 2y +6z +8 = 0 would be the eqaution of the plane

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

no i wrote it as it is

- anonymous

that isn't in the answer choices

- amistre64

what are the answer choices :)

- anonymous

ok give me a secon it's kind of a lot to type out

- amistre64

k

- anonymous

its looks line parametric representation of the line... what is the topic of your study?

- anonymous

a) x=2+2t, y=2+3t, z=-3+t b)x=2+3t, y=2+2t, z=-3+6t c)x=2+2t, y=2-3t, z=-3-t d)x=2+3t, y=2-2t, z=-3-6t

- anonymous

this is cal 3...can you help?

- anonymous

still there?

- amistre64

a) x=2+2t, y=2+3t, z=-3+t
b)x=2+3t, y=2+2t, z=-3+6t
c)x=2+2t, y=2-3t, z=-3-t
d)x=2+3t, y=2-2t, z=-3-6t
my guess is (b) but i have no proof to back that up......its been awhile :)

- anonymous

ok thanks for looking

- amistre64

To find the parametric equations of the line passing through the point (2,2,-3) and parallel to the vector <3,2,6>.
We first find the vector equation of the line. Here, r_0=<2,2,-3> and v=<3,2,6>.
Thus, the line has vector equation r=<2,2,-3>+t<3,2,6>.
The parametric equations of the line are:
x=2+3t, y=2+2t, and z=-3+6t. [B]

- amistre64

copied that off the web and included your numbers :)
http://www.math.oregonstate.edu/home/programs/undergrad/CalculusQuestStudyGuides/vcalc/lineplane/lineplane.html

Looking for something else?

Not the answer you are looking for? Search for more explanations.