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anonymous

  • 5 years ago

Ten students are applying for 3 positions on a team. the students include 4 boys (adam, alex, anthony, and arnold) and 6 girls (abbey, aurora, agnes, alice, amanda, and anna). all the students have an equal chance of being selected. find the probability that the students selected will include: a) at most 1 girl b) adam, anthony, and alice c) agnes and 2 other students

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  1. anonymous
    • 5 years ago
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    no idea

  2. anonymous
    • 5 years ago
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    hey INewton

  3. amistre64
    • 5 years ago
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    we could always do this the long way :) and make a tree or chart

  4. amistre64
    • 5 years ago
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    i havent been good yet at finding and filtering out all the redundnat possibilities :)

  5. anonymous
    • 5 years ago
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    can u do it using permutations and combinations?

  6. amistre64
    • 5 years ago
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    not yet, taking stats this summer...can you wait til august :)

  7. anonymous
    • 5 years ago
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    ur taking ap stats?

  8. amistre64
    • 5 years ago
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    college class...

  9. amistre64
    • 5 years ago
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    im too old for ap i think

  10. anonymous
    • 5 years ago
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    oh do u know the answers though???

  11. amistre64
    • 5 years ago
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    not any anwers that i would trust; is there a multiple choice with this?

  12. anonymous
    • 5 years ago
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    no

  13. amistre64
    • 5 years ago
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    I know that with 3 positions avaiable; there are 10*9*8 possibilities; but how to remove the duplicates eludes me at the moment

  14. amistre64
    • 5 years ago
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    we can always try to work with a similar situation; such as 2 spots to fill and 4 people; then see how to eliminate the duplicates

  15. anonymous
    • 5 years ago
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    try it

  16. anonymous
    • 5 years ago
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    The idea is that you try it.

  17. anonymous
    • 5 years ago
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    (although admittedly it's not personally how I would do it - but I hate statistics anyway)

  18. amistre64
    • 5 years ago
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    dividing the total by 2 worked in that case on paper; let me try another

  19. anonymous
    • 5 years ago
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    ?????

  20. amistre64
    • 5 years ago
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    11 21 31 41 12 22 32 42 13 23 33 43 14 24 34 44

  21. amistre64
    • 5 years ago
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    cross off all the duplicates

  22. amistre64
    • 5 years ago
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    12 13 23 14 24 34

  23. amistre64
    • 5 years ago
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    the total possible combination of 4 people and 2 spots is: 4*3/2

  24. amistre64
    • 5 years ago
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    its the same for 5 people and 2 spots: 5*4/2

  25. amistre64
    • 5 years ago
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    i wonder whatll happen with 3 spots...

  26. anonymous
    • 5 years ago
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    ??????

  27. amistre64
    • 5 years ago
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    4 people and 3 spots has 4 possibilities

  28. amistre64
    • 5 years ago
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    how we factorial that I dont know...

  29. amistre64
    • 5 years ago
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    3C4 maybe.. let me find an online cal

  30. amistre64
    • 5 years ago
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    the formula is: people! ----------------- spots!(people-spots)!

  31. amistre64
    • 5 years ago
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    and thats the best i can do for you at the moment...

  32. amistre64
    • 5 years ago
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    there seems to be 120 possible combonations; without repetition in all

  33. anonymous
    • 5 years ago
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    wait, so what's c d and e??

  34. amistre64
    • 5 years ago
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    4 boys can form an all boy team 4 times; so I would think that the rest are sure to have at least 1 girl; 116 out of 120 is sure to have at least 1 girl

  35. amistre64
    • 5 years ago
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    c is agnus plus 2 other students; so we can take agnus out of the mix and have 2 spots to fill; 9! ------- = 36 2!(9-2)!

  36. amistre64
    • 5 years ago
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    36 out of 120

  37. amistre64
    • 5 years ago
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    what does it mean by positions? like captain, assistant, and runner? then we can have duplicates, just not the same person in all 3 spots and that changes things

  38. anonymous
    • 5 years ago
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    d is 36/120???

  39. anonymous
    • 5 years ago
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    ????????

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