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we could always do this the long way :) and make a tree or chart
i havent been good yet at finding and filtering out all the redundnat possibilities :)
can u do it using permutations and combinations?
not yet, taking stats this summer...can you wait til august :)
ur taking ap stats?
im too old for ap i think
oh do u know the answers though???
not any anwers that i would trust; is there a multiple choice with this?
I know that with 3 positions avaiable; there are 10*9*8 possibilities; but how to remove the duplicates eludes me at the moment
we can always try to work with a similar situation; such as 2 spots to fill and 4 people; then see how to eliminate the duplicates
The idea is that you try it.
(although admittedly it's not personally how I would do it - but I hate statistics anyway)
dividing the total by 2 worked in that case on paper; let me try another
11 21 31 41 12 22 32 42 13 23 33 43 14 24 34 44
cross off all the duplicates
12 13 23 14 24 34
the total possible combination of 4 people and 2 spots is: 4*3/2
its the same for 5 people and 2 spots: 5*4/2
i wonder whatll happen with 3 spots...
4 people and 3 spots has 4 possibilities
how we factorial that I dont know...
3C4 maybe.. let me find an online cal
the formula is: people! ----------------- spots!(people-spots)!
and thats the best i can do for you at the moment...
there seems to be 120 possible combonations; without repetition in all
wait, so what's c d and e??
4 boys can form an all boy team 4 times; so I would think that the rest are sure to have at least 1 girl; 116 out of 120 is sure to have at least 1 girl
c is agnus plus 2 other students; so we can take agnus out of the mix and have 2 spots to fill; 9! ------- = 36 2!(9-2)!
36 out of 120
what does it mean by positions? like captain, assistant, and runner? then we can have duplicates, just not the same person in all 3 spots and that changes things
d is 36/120???