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anonymous

  • 5 years ago

jane works north of her home. her husband Bob works east. they leave for work at the same time. By the time Jane is 7 miles from home, the distance between them is one mile more than Bobs distance from home. How far from home is bob?

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  1. anonymous
    • 5 years ago
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    theorem of pythagoras i would say

  2. anonymous
    • 5 years ago
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    7^2 + (x)^2 = (x+1)^2

  3. anonymous
    • 5 years ago
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    this produces the quadratic \[49 + x ^{2} = x^2 + 2x + 1\]

  4. anonymous
    • 5 years ago
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    x=24

  5. anonymous
    • 5 years ago
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    i dont understand quadratics =(

  6. anonymous
    • 5 years ago
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    u dont have to in this case as you may simply subtract x^2 from both sides and you get a linear equation in x which is then solved by subtracting one from both sides and dividing by 2

  7. anonymous
    • 5 years ago
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    i dont understand any of it =(

  8. anonymous
    • 5 years ago
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    pythagoras theorem states \[hypthenuse^2 = adjacent^2 + opposite^2\]

  9. anonymous
    • 5 years ago
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    can u see how their movements form a right angled triangle? draw it for urself

  10. anonymous
    • 5 years ago
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    i thought it was a +b=c

  11. anonymous
    • 5 years ago
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    pythagoras' theorem? no the sides are squared

  12. anonymous
    • 5 years ago
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    i dont understand. sorry

  13. anonymous
    • 5 years ago
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    start by drawing the problem. mark a dot on the page for their home and then take a line 7 north for janes movement.

  14. anonymous
    • 5 years ago
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    now go back to the dot and take a line east for the dot (length doesnt matter) let this line have length x

  15. anonymous
    • 5 years ago
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    ok

  16. anonymous
    • 5 years ago
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    now mark the positions of mary and bob by a dot. now join those two dots and let the length of this new line be x+1 because the question says the distance between them is one more than how far bob is from home

  17. anonymous
    • 5 years ago
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    ok

  18. anonymous
    • 5 years ago
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    now can you see the right angled triangle? the hypothenuse (longest side) has length x+1. apply pythagoras theorem to get \[7^2 + (x)^2 = (x+1)^2\]

  19. anonymous
    • 5 years ago
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    then solve for x

  20. anonymous
    • 5 years ago
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    7x to the 4th = 2x+2?? i dont know what im doing...im far from help

  21. anonymous
    • 5 years ago
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    i think you are confused between powers of a number and mulitplication\[(x+1)^2 = (x+1)(x+1) = x^2 +x + x +1 = x^2 +2x +1\]

  22. anonymous
    • 5 years ago
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    which is the right hand side, left hand side is just 49 + x^2

  23. anonymous
    • 5 years ago
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    omg 49 +2x=2x??

  24. anonymous
    • 5 years ago
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    almost \[49+x^2 = x^2 + 2x + 1 \rightarrow 49 = 2x +1 \rightarrow 2x=48 \]

  25. anonymous
    • 5 years ago
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    hm

  26. anonymous
    • 5 years ago
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    verify the steps yourself to make sure u understand

  27. anonymous
    • 5 years ago
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    i dont

  28. anonymous
    • 5 years ago
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    49+x times x=(x+1)(x+1)

  29. anonymous
    • 5 years ago
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    yes correct

  30. anonymous
    • 5 years ago
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    only i dont know how to answer that 49x2=x2+1x+1?

  31. anonymous
    • 5 years ago
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    thank you for your help

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