anonymous
  • anonymous
How the heck do I write a set builder and interval out of 6-8(y+3)+5y>(2y-5)+13? once I worked it out I got y<-6m whats my next step?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
where did the m come from in your answer?
anonymous
  • anonymous
thats a typo, I'm sorry.
anonymous
  • anonymous
y<-6

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anonymous
  • anonymous
\[let s = \left\{ y: y<-6 \right\}\]
anonymous
  • anonymous
in set builder, then the interval \[y \in \left( -6, -\infty \right)\]
anonymous
  • anonymous
so how do I know where to put the infinity sign?
anonymous
  • anonymous
oh wait i miss typed that, the -6 and - infinity shud be swapped. sorry
anonymous
  • anonymous
the smaller value should always be on the left by convention since the interval starts at the left hand value and goes up to the right hand value
anonymous
  • anonymous
so when do I use that squiggly line, and bracets instead of perenthisis?
anonymous
  • anonymous
round brackets mean the endpoints arent in the interval and square brackets mean they are included
anonymous
  • anonymous
so whats the interval to this specific one? \[\xi x-6\]
anonymous
  • anonymous
im not sure i understand your notation, what does the lowercase delta stand for?
anonymous
  • anonymous
Our professor was asking for some squiggly line for example: 8-6(x-3)>-4x+12 Solution: x<7 Set Builder Notation:\[\xi x-1+<7\xi\] Interval Notation: (-\[\infty , 5/2]\]
anonymous
  • anonymous
I'm sorry the interval notation is actually 7 not 5/2, but do you see what I mean?
anonymous
  • anonymous
maybe its just the name he is using but in any book i have ever seen set builder means { } and u state the conditions for membership of the set in the brackets
anonymous
  • anonymous
yes, maybe it is {
anonymous
  • anonymous
so to graph y<-6 it would be <_______O I I I I I I I I I I -6

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