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anonymous

  • 5 years ago

How the heck do I write a set builder and interval out of 6-8(y+3)+5y>(2y-5)+13? once I worked it out I got y<-6m whats my next step?

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  1. anonymous
    • 5 years ago
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    where did the m come from in your answer?

  2. anonymous
    • 5 years ago
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    thats a typo, I'm sorry.

  3. anonymous
    • 5 years ago
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    y<-6

  4. anonymous
    • 5 years ago
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    \[let s = \left\{ y: y<-6 \right\}\]

  5. anonymous
    • 5 years ago
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    in set builder, then the interval \[y \in \left( -6, -\infty \right)\]

  6. anonymous
    • 5 years ago
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    so how do I know where to put the infinity sign?

  7. anonymous
    • 5 years ago
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    oh wait i miss typed that, the -6 and - infinity shud be swapped. sorry

  8. anonymous
    • 5 years ago
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    the smaller value should always be on the left by convention since the interval starts at the left hand value and goes up to the right hand value

  9. anonymous
    • 5 years ago
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    so when do I use that squiggly line, and bracets instead of perenthisis?

  10. anonymous
    • 5 years ago
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    round brackets mean the endpoints arent in the interval and square brackets mean they are included

  11. anonymous
    • 5 years ago
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    so whats the interval to this specific one? \[\xi x-6\]

  12. anonymous
    • 5 years ago
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    im not sure i understand your notation, what does the lowercase delta stand for?

  13. anonymous
    • 5 years ago
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    Our professor was asking for some squiggly line for example: 8-6(x-3)>-4x+12 Solution: x<7 Set Builder Notation:\[\xi x-1+<7\xi\] Interval Notation: (-\[\infty , 5/2]\]

  14. anonymous
    • 5 years ago
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    I'm sorry the interval notation is actually 7 not 5/2, but do you see what I mean?

  15. anonymous
    • 5 years ago
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    maybe its just the name he is using but in any book i have ever seen set builder means { } and u state the conditions for membership of the set in the brackets

  16. anonymous
    • 5 years ago
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    yes, maybe it is {

  17. anonymous
    • 5 years ago
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    so to graph y<-6 it would be <_______O I I I I I I I I I I -6

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spraguer (Moderator)
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