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anonymous
 5 years ago
Ten students are applying for 3 positions on a team. the students include 4 boys (adam, alex, anthony, and arnold) and 6 girls (abbey, aurora, agnes, alice, amanda, and anna). all the students have an equal chance of being selected. find the probability that the students selected will include: a) at most 1 girl b) adam, anthony, and alice c) agnes and 2 other students
anonymous
 5 years ago
Ten students are applying for 3 positions on a team. the students include 4 boys (adam, alex, anthony, and arnold) and 6 girls (abbey, aurora, agnes, alice, amanda, and anna). all the students have an equal chance of being selected. find the probability that the students selected will include: a) at most 1 girl b) adam, anthony, and alice c) agnes and 2 other students

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0naww not in college lol :P highschool why'd u think im in college?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the first one should be (4/10)^3 + (6/10)^1 x (4/10)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you have answers to confirm?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i was working on his question until you answered it. i was simply wondering why theis person thought i was in college. he asked me a question, i was answering.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0second one should be (6/10)^1 x (4/10)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it with replacement or without? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i always get confused with statistics

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you may have to use hypergeometric forumula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wwhat i wrote is binomial

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, you certainly don't 'have to'  if one really wanted to they could solve this by just drawing a (massive) tree diagram, but I think we can be slightly more clever about it,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm maybe (6/10)(4/9)(3/8) x 3 + (4/10)(3/9)(2/8)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0crap i'm so confused with this i should just stop lol. gl with the problem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't have answers to go with this.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0anyone figure this out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Don't worry, you can just draw a treediagram with 720 branches and be sure of the answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0[(6/10)(4/9)(3/8) + (4/10)(6/9)(3/8) + (4/10)(3/9)(6/8)] + (4/10)(3/9)(2/8)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait the ordering doesn't matter so you have to divide the first part by 3? or 6?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I preferred it in the old form you posted: (6/10)(4/9)(3/8) x 3 + (4/10)(3/9)(2/8)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0only problem with that is you don't know girl is selected before boys

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You don't. But your answer there accounts for it by multiplying by three.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i don't know stat well enough to figure this out without final answer unfortunatley

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK. If there are three boys chosen, the chance is (clearly... I hope) (4/10)(3/9)(2/8) The only other option is 1 girl and 2 boys. This can either be GBB, BGB, BBG, but the chance of each is still (6x4x3)/(10x8x9). So your answer \[\frac{(6 \times 4 \times 3) \times 3 + 4 \times 3 \times 2}{720} \] is right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0even though probability of getting boy or girl is different?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh wait you already accounted for that lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes; there's still a total number of 10*9*8 = 720 in the denominator; the order of the multiplication above is irrelevant. @ azntiger627  FACEPALM  if you honestly have no idea which part this is then you have clearly done nothing on this work, and do not deserve help until at least attempt it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just came back from dinner lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wasting time eating... when you have Maths to do!? That's a cardinal sin in my book.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol sorry, now I'm rdy, so which part were u guys talking about?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'll tell you. But you have to guess first.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so what did u find out so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Newton already solved part (a) for you above. but i think you should go over permutations and combinations before trying to solve the question above. good luck!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You solved it first :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for d, i'm guessing (4C2)(6C1) / 10C3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Very funny, Mr; there is no D.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that correct though?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That equal 3/10  does that seem correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea I got 3/10, is it correct though?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There are 720 possibilities, and you think 216 contain the same three people? (they don't)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do u think then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't 'think' anything; I know what the answer is.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i will look at it soon, im tied up atm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There names all begin with A, which is annoying, so just called them ABC. There are 6 ways of arranging them: ABC ACB etc. And 10 x 9 x 8 possible ways in total. Continue from there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Their names* UGGGGGGGGGH grammar fail.
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