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anonymous
 5 years ago
The number of cells of a certain type of bacteria increases continuously at a rate equal to two
more than three times the number of bacteria present. If there are 10 present initially, and 42 present T hours
later, find the exact value of T
anonymous
 5 years ago
The number of cells of a certain type of bacteria increases continuously at a rate equal to two more than three times the number of bacteria present. If there are 10 present initially, and 42 present T hours later, find the exact value of T

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's a simple linear equation, relating y as a function of t. For example, you have y as the number of bacteria, and t as hours. Therefore, using the formula y=mx + b, you get y=(2+ 3y)t + 10 Solve for t by substituting in 42 for y and trucating.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know what my xvalue would be?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The correct answer is (1/3)ln(4) but I don't know how to get it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You don't have an x value. I used y in my example because It is the output, but the independent variable is t. If their answer is in terms of natural log then you must go about it more specifically, using the formula k=Ce^rt

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't completely understand. Do you mind helping me solve it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is exponential growth\[A = Ae^{rt}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[A = Pe^{rt}\] scratch the first one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah same formula. Just put in the values you have and solve for the time
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