anonymous
  • anonymous
The number of cells of a certain type of bacteria increases continuously at a rate equal to two more than three times the number of bacteria present. If there are 10 present initially, and 42 present T hours later, find the exact value of T
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
It's a simple linear equation, relating y as a function of t. For example, you have y as the number of bacteria, and t as hours. Therefore, using the formula y=mx + b, you get y=(2+ 3y)t + 10 Solve for t by substituting in 42 for y and trucating.
anonymous
  • anonymous
Do you know what my x-value would be?
anonymous
  • anonymous
The correct answer is (1/3)ln(4) but I don't know how to get it

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anonymous
  • anonymous
You don't have an x value. I used y in my example because It is the output, but the independent variable is t. If their answer is in terms of natural log then you must go about it more specifically, using the formula k=Ce^rt
anonymous
  • anonymous
I don't completely understand. Do you mind helping me solve it?
anonymous
  • anonymous
This is exponential growth\[A = Ae^{rt}\]
anonymous
  • anonymous
\[A = Pe^{rt}\] scratch the first one
anonymous
  • anonymous
Yeah same formula. Just put in the values you have and solve for the time

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