anonymous
  • anonymous
Ten students are applying for 3 positions on a team. the students include 4 boys (adam, alex, anthony, and arnold) and 6 girls (abbey, aurora, agnes, alice, amanda, and anna). all the students have an equal chance of being selected. find the probability that the students selected will include: a) adam, anthony, and alice b) agnes and 2 other students
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
ok
anonymous
  • anonymous
adam anthony and alice, thats 3 people so favorable is 3. and total is 10 choose 3 , correct ?
anonymous
  • anonymous
so 3 / 10 choose 3

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More answers

anonymous
  • anonymous
3 / ( 10 choose 3) , remember 10 choose 3 is total ways of choosing 3 people out of ten , order does not count
anonymous
  • anonymous
that's it?
anonymous
  • anonymous
and 3 cuz you have 3 favorable, they specified
anonymous
  • anonymous
yeah, its easy :0
anonymous
  • anonymous
well that one anyway
anonymous
  • anonymous
brb
anonymous
  • anonymous
wait so answer is????
anonymous
  • anonymous
.025
anonymous
  • anonymous
fraction form?
anonymous
  • anonymous
3 / ( 120
anonymous
  • anonymous
1/40
anonymous
  • anonymous
wait, why does it matter?
anonymous
  • anonymous
probability is usually in fraction form
anonymous
  • anonymous
if youre doing this online, let me know if its correct
anonymous
  • anonymous
it can be a decimal between 0 and 1
anonymous
  • anonymous
ok
anonymous
  • anonymous
B now
anonymous
  • anonymous
wait, is it right ?
anonymous
  • anonymous
I'm not sure? going over it on monday
anonymous
  • anonymous
in class
anonymous
  • anonymous
let's do B
anonymous
  • anonymous
Lol
anonymous
  • anonymous
ok agnes, thats 1
anonymous
  • anonymous
2 other students? well there are 9 students left, and you choose 2
anonymous
  • anonymous
so 1 + 9 choose 2 , thats the favorable , and the denominator is again , the same
anonymous
  • anonymous
newton, do you concur?
anonymous
  • anonymous
( 1 + 9 C 2 ) / ( 10 C 3 )
anonymous
  • anonymous
oh newton is gone, darn
anonymous
  • anonymous
why did u add 1??
anonymous
  • anonymous
Oh by the way, if the answer to the first one is 1/40, and there are 10 * 9 * 8 ways of choosing the first 3 people, that implies that 18 teams will have those three in any order (they don't)
anonymous
  • anonymous
1 for agnes, since they told you , you must choose her
anonymous
  • anonymous
It makes more sense just to say there are 10C3 ways of picking the 3 students (nCr takes into account the ordering problem) and one of these will be the 3 we want - so it is simply 1/10C3, not 3/10C3
anonymous
  • anonymous
what??? I'm confused. what's the setup
anonymous
  • anonymous
i get 37/120 , unless i did something wrong
anonymous
  • anonymous
or should it be multiplied, hmmm
anonymous
  • anonymous
ohhh
anonymous
  • anonymous
sorry it is ( 1 * 9 choose 2 ) / 10 choose 3
anonymous
  • anonymous
since there is 1 way to choose agnes, then there is 2 you have to choose among the 9 left
anonymous
  • anonymous
so 36/ 120 = 3/ 10
anonymous
  • anonymous
ah I see lol, but I still don't understand this permutation and combination stuff? is there a way that u can explain to me?
anonymous
  • anonymous
permutations is where order counts, combination is where order does not count
anonymous
  • anonymous
thats the "big" difference
anonymous
  • anonymous
how do u know what numbers to put for the probability
anonymous
  • anonymous
like 9C2/10C3
anonymous
  • anonymous
I don't get how u set up the numbers in order to find the probability
anonymous
  • anonymous
well we use multiplication rule
anonymous
  • anonymous
there are how many ways to choose agnes, one way. and for each of that way we can choose from whats left (9 people) 2 people we can choose. so we multiply these .
anonymous
  • anonymous
if you can do step one in k ways, and for each of those ways you can do step m, then there are a total of k * m ways
anonymous
  • anonymous
so we did ( 1 * 9C2) , thats the favorable
anonymous
  • anonymous
what grade r u in btw

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