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anonymous

  • 5 years ago

Ten students are applying for 3 positions on a team. the students include 4 boys (adam, alex, anthony, and arnold) and 6 girls (abbey, aurora, agnes, alice, amanda, and anna). all the students have an equal chance of being selected. find the probability that the students selected will include: a) adam, anthony, and alice b) agnes and 2 other students

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  1. anonymous
    • 5 years ago
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    ok

  2. anonymous
    • 5 years ago
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    adam anthony and alice, thats 3 people so favorable is 3. and total is 10 choose 3 , correct ?

  3. anonymous
    • 5 years ago
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    so 3 / 10 choose 3

  4. anonymous
    • 5 years ago
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    3 / ( 10 choose 3) , remember 10 choose 3 is total ways of choosing 3 people out of ten , order does not count

  5. anonymous
    • 5 years ago
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    that's it?

  6. anonymous
    • 5 years ago
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    and 3 cuz you have 3 favorable, they specified

  7. anonymous
    • 5 years ago
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    yeah, its easy :0

  8. anonymous
    • 5 years ago
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    well that one anyway

  9. anonymous
    • 5 years ago
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    brb

  10. anonymous
    • 5 years ago
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    wait so answer is????

  11. anonymous
    • 5 years ago
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    .025

  12. anonymous
    • 5 years ago
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    fraction form?

  13. anonymous
    • 5 years ago
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    3 / ( 120

  14. anonymous
    • 5 years ago
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    1/40

  15. anonymous
    • 5 years ago
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    wait, why does it matter?

  16. anonymous
    • 5 years ago
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    probability is usually in fraction form

  17. anonymous
    • 5 years ago
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    if youre doing this online, let me know if its correct

  18. anonymous
    • 5 years ago
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    it can be a decimal between 0 and 1

  19. anonymous
    • 5 years ago
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    ok

  20. anonymous
    • 5 years ago
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    B now

  21. anonymous
    • 5 years ago
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    wait, is it right ?

  22. anonymous
    • 5 years ago
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    I'm not sure? going over it on monday

  23. anonymous
    • 5 years ago
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    in class

  24. anonymous
    • 5 years ago
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    let's do B

  25. anonymous
    • 5 years ago
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    Lol

  26. anonymous
    • 5 years ago
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    ok agnes, thats 1

  27. anonymous
    • 5 years ago
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    2 other students? well there are 9 students left, and you choose 2

  28. anonymous
    • 5 years ago
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    so 1 + 9 choose 2 , thats the favorable , and the denominator is again , the same

  29. anonymous
    • 5 years ago
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    newton, do you concur?

  30. anonymous
    • 5 years ago
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    ( 1 + 9 C 2 ) / ( 10 C 3 )

  31. anonymous
    • 5 years ago
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    oh newton is gone, darn

  32. anonymous
    • 5 years ago
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    why did u add 1??

  33. anonymous
    • 5 years ago
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    Oh by the way, if the answer to the first one is 1/40, and there are 10 * 9 * 8 ways of choosing the first 3 people, that implies that 18 teams will have those three in any order (they don't)

  34. anonymous
    • 5 years ago
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    1 for agnes, since they told you , you must choose her

  35. anonymous
    • 5 years ago
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    It makes more sense just to say there are 10C3 ways of picking the 3 students (nCr takes into account the ordering problem) and one of these will be the 3 we want - so it is simply 1/10C3, not 3/10C3

  36. anonymous
    • 5 years ago
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    what??? I'm confused. what's the setup

  37. anonymous
    • 5 years ago
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    i get 37/120 , unless i did something wrong

  38. anonymous
    • 5 years ago
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    or should it be multiplied, hmmm

  39. anonymous
    • 5 years ago
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    ohhh

  40. anonymous
    • 5 years ago
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    sorry it is ( 1 * 9 choose 2 ) / 10 choose 3

  41. anonymous
    • 5 years ago
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    since there is 1 way to choose agnes, then there is 2 you have to choose among the 9 left

  42. anonymous
    • 5 years ago
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    so 36/ 120 = 3/ 10

  43. anonymous
    • 5 years ago
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    ah I see lol, but I still don't understand this permutation and combination stuff? is there a way that u can explain to me?

  44. anonymous
    • 5 years ago
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    permutations is where order counts, combination is where order does not count

  45. anonymous
    • 5 years ago
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    thats the "big" difference

  46. anonymous
    • 5 years ago
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    how do u know what numbers to put for the probability

  47. anonymous
    • 5 years ago
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    like 9C2/10C3

  48. anonymous
    • 5 years ago
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    I don't get how u set up the numbers in order to find the probability

  49. anonymous
    • 5 years ago
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    well we use multiplication rule

  50. anonymous
    • 5 years ago
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    there are how many ways to choose agnes, one way. and for each of that way we can choose from whats left (9 people) 2 people we can choose. so we multiply these .

  51. anonymous
    • 5 years ago
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    if you can do step one in k ways, and for each of those ways you can do step m, then there are a total of k * m ways

  52. anonymous
    • 5 years ago
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    so we did ( 1 * 9C2) , thats the favorable

  53. anonymous
    • 5 years ago
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    what grade r u in btw

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