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anonymous
 5 years ago
(3^1xy^4z^5)/(7x^4y^2z)
 Simplify Completely
anonymous
 5 years ago
(3^1xy^4z^5)/(7x^4y^2z)  Simplify Completely

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(I got 9y^12z^2)/(14x^10z^10)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First write all the variables in the places they should be. If it's negative, it switches from top to bottom, or vice versa. Then we get: \[x z ^{5} x ^{4} \div 3 (7) y ^{4} y ^{2} z\] Then you combine like terms: \[x ^{5} z ^{5} \div 21 z y ^{6}\] Then finally you cancel the exponents that you can. The only one you can change is the z, so it becomes: \[x ^{5} z ^{4} \div 21 y ^{6}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh... I missed something in my problem... I forgot about the ( )^2 that surrounds the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, thats okay. You still do the same thing. Only take all of my answer, flip all of them, ie the bottom becomes the top and vice versa, and square them all. It doesn't change anything other than that.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But to save another explanation, if a fraction is surrounded by ( )^2, don't you take the top part of the problem and move it to the bottom?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, then multiply all the exponents by 2, and the 21 is squared.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay great, tyvm for taking the time to help me :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sure no problem! I like medals if it helped haha
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