anonymous
  • anonymous
how many different comminities can be formed from 12 teachers, and 40 students, if the commitie consists 3 teachers and 4 students? In how many ways can the commitie of 7 members be selected?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
find each seaprately (teachers and students) in the same way you have been, then multiply the two answers that you get.
anonymous
  • anonymous
and then how does 7 come in?
anonymous
  • anonymous
I keep getting a decimal for a number :/

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anonymous
  • anonymous
i can show u what I did
anonymous
  • anonymous
out of 12 teachers you choose 3 = 12C3 and out of 40 students you choose 4 = 40C4
anonymous
  • anonymous
Do those separately, then multiply the answers you get
anonymous
  • anonymous
No decimals should show up
anonymous
  • anonymous
for the 40 students is it 40*39*38*37?
anonymous
  • anonymous
or is that when u do the 4?
anonymous
  • anonymous
for Choosing when order doesn't matter, do 40*39*38*37 and then divide by 4*3*2*1 Similar for the teachers
anonymous
  • anonymous
teachers is 12*11*10 divided by 3*2*1 --> notice that you get the same number of factors in the numerator as the denominator
anonymous
  • anonymous
ok so now i got 91390 and then for the teachers 220
anonymous
  • anonymous
multiply for a very large number

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