A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
(x^22x+4/x^25x+6)divided by(x^3+8/x^29)
anonymous
 5 years ago
(x^22x+4/x^25x+6)divided by(x^3+8/x^29)

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[[(x^22x+4)\div(x^25x+6)] \div[(x^3+8/x^29)]\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Multiply the second part by the numerator and simplify.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I factored down to the following: \[[(x2)(x2)/(x6)(x1)]*[(x3)(x+3)/(x+2)(x^22x+4)]\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But there are no like terms, so do you just combine all of the factors into one problem? I got this as my answer so far: \[(x2)^2(x3)(x+3)/(x1)(x6)(x+2)(x^22x+4)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You flip the second part, then multiply them out. Factoring is unnecessary.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I did flip the terms, but the bases aren't the same.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You're multiplying. It doesn't matter if the bases are the same. That only matters with addition and subtraction of fractions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So my answer is still technically right, I just have to multiply everything out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Leave it unfactored, flip it, and multiply through.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But why include fractions that contain the difference and sums of two squares and cubes if you weren't supposed to factor them?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Because you're not solving for the roots of x. You'd have to multiply it all out all over again anyway, and make things VERY difficult for yourself. Itd be redundant.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Multiplying all of that out would take an entire page, and isn't factoring simplifying a problem? My instructions say to simplify completely.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(didn't include that above, which is my bad)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to factor AFTER simplifying, and AFTER multiplying... Otherwise nothing is simplified, and it's redundant and unnecessary.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That and you didn't factor correctly, so I'd want to avoid that.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you are saying I should take \[(x^22x+4)(x^29)\] and so on?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes. Then post what you get.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The numerator should be x^4 2x^3 + 4x^2 9x^2 +18x 36 simplify and factor that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^42x^35x^218x36\] for above then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I had 9x^2+4x^2=5x^2. Does that check out with you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Numerator yes. I'm not sure what you mean by the second post though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For the numerator, it is fine though. That gives me plenty to work with, thank you again :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\left(\frac{42 x+x^2}{(3+x) (2+x)}\right)\left(\frac{(3+x) (3+x)}{(2+x) \left(42 x+x^2\right)}\right)=\frac{3+x}{4+x^2} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Left Side = Right Side when both are evaluated with x=19
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.