A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    never ?

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You have\[x^y.x^z=x^{yz}\]We know, by exponent laws, \[x^y.x^z=x^{y+z}\]so\[x^{y+z}=x^{yz}\]only if\[y+z=zy\]If you assume that it is always true, you are assuming\[y+z=yz\]for any y, z real. So choose y=1 and z=1. The LHS will be 2 and the RHS will be 1. This is a contradiction, so it's not true for all y and z. But, there will be cases when it is true. From the exponent equation above,\[y+z-zy=0\]and so\[y(1-z)+z=0\]That is,\[y=\frac{z}{z-1}\]So, if we choose a z, and then a y as given by the formula, we'll have that\[x^y.x^z=x^{yz}\]So your statement is *sometimes* true.

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank, you get medal for this

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You're welcome.

  5. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i know the answer its4x67xuyx=9

  6. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.