anonymous
  • anonymous
In the figure above, AB is the diameter of the circle with center O and ABCD is a square. What is the area of the shaded region in terms of r? see attachment for figure
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
r^2[4-(pi/2)] look bc=ab=2r right area of sqare=ab*bc=2r*2r=4r^2 area of half circle=(pi*r^2)/2 shaded area = area of sqare-area of half circle =>(4r^2)-(pi*r^2)/2 therefore answer :r^2[4-(pi/2)]
anonymous
  • anonymous
did zat help?

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anonymous
  • anonymous
[(2r)^2]-[(r^2*pi)/2] You have to subtract area of the half circle from area of the square.
anonymous
  • anonymous
thank u reza.

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