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cherrilyn
 5 years ago
evaluate the integral
cherrilyn
 5 years ago
evaluate the integral

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cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?}(x ^{2}x+1) dx/ x ^{2}x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to give us a hint. Which part of the book are you at?

cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0hehe. partial functions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[LHS =A/(X1) +B(x+1)\]

cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0umm.... wouldn't it be Ax+B/x^2+x? or are you skipping steps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, I haven't done these in a while, may be you should start it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, the bottom is not the difference of two squares, I misread it.

cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0can you only use long division if the denominator is the difference of two squares?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[LHS =A/x + B/(x1)\]

cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0okay so what should I do next

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can handle it now. It is cut up in small bites that you can chew on.

cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0I got A = 1 and B =1 but when I find the integral my denominator = 0 :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what , just equals ln(x) +ln(x1) +C

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can be simplifed as ln [ (x1)/(x) ] +C
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