Determine whether the improper integral converges, and if so, evaluate it.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Determine whether the improper integral converges, and if so, evaluate it.

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[\int\limits_{5}^{6} dx/(x-5)^{3/2}\]
\[=\frac{-2}{\sqrt{x-5}} \] from 5 to 6 =-2 - (-infinity)=infinity so it diverges
what were the new bounds?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

what do you mean? im sorry i used the bounds 5 to 6, and technically took the limit as x goes to 5
aren't the limits supposed to include an infinity somewhere or no?
not always it depends on the problem, since our problem has bounds already of 5 and 6 we are checking the limit of the integral from a to 6 as a ->5
ahh gotcha. thanks!

Not the answer you are looking for?

Search for more explanations.

Ask your own question