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anonymous
 5 years ago
find the derivative of y=arccos(sinx)
anonymous
 5 years ago
find the derivative of y=arccos(sinx)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let u =sin(x) y= cos^1(u) dy/dx = dy/du * du/dx = 1 / sqrt ( 1u^2) * cos(x) dy/dx = cos(x) / sqrt (1sin^2 x ) = cos(x) /cos(x) =1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whoops should be cos(x) /cos(x) = 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what are you doing when you do dy/du*du/dx=1?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry just dy/du*du/dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ \frac{d}{dx} \cos^{1}(x) = \frac{1}{\sqrt{1x^2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ \frac{d}{dx} \cos^{1}(u) = \frac{1}{\sqrt{1x^2}} \frac{du}{dx}\]
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