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anonymous
 5 years ago
If f(x)=sinx+cosx, find the values of n for which (f(x))^n=f(x)
anonymous
 5 years ago
If f(x)=sinx+cosx, find the values of n for which (f(x))^n=f(x)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ie when [f(x)]^n  f(x) =0 f(x) [ ( f(x) )^(n1) 1 ] =0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so f(x) =0 , or [ f(x)]^(n1) = 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x) =0 > gives nothing [f(x)]^(n1) = 1 > gives n1 = 0 , n=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer says 4i, i E N

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got one too but I don't understand how to get 4i
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