anonymous
  • anonymous
SOMEONE PLEASE HELP! A rectangular yard measuring 40 ft by 71ft is bordered (and surrounded) by a fence. Inside, a walk that is 3 ft wide goes all the way along the fence. Find the area of this walk. Be sure to include the correct unit in your answer.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
is 40ft the length and 71ft the width of the yard?
anonymous
  • anonymous
i'm guessing. that is how it is written. so yes.
anonymous
  • anonymous
it is worded really weird

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More answers

anonymous
  • anonymous
ok then, if 40ft is the length, u can multiply that times the width of the walk, so 3 ft, 40*3= 120...i think that would be the area 120 sq ft
anonymous
  • anonymous
it said that was incorrect
anonymous
  • anonymous
it will show me how to do it. and iwill tell u. then will u heelp me with the next 2 problems like this one?
anonymous
  • anonymous
sure ill try to help u
anonymous
  • anonymous
We start by drawing a rectangle representing the fence surrounding the yard. Inside the fence, we draw a wide walk going along the fence. inner rectangle's length is the yard length twice the walk width. so 71-3-3=65 ft and the width is 40-3-3=34 ft
anonymous
  • anonymous
since the walk is the region between the 2 rectangles..it's area is the area of the larger rectangle minus the area of the smaller rectangle. so a=40x71-34x65 =2840-2210 =630 ft ^2
anonymous
  • anonymous
follow? bc it's kinda confusing to me.
anonymous
  • anonymous
yes, i think i follow
anonymous
  • anonymous
ok, i got it :)
anonymous
  • anonymous
it sounds more like a rectangular box?
anonymous
  • anonymous
i know. this thing is so stupid..but i think i have the hang of it now.
radar
  • radar
It kinda makes sense, otherwise you might include the corners twice.
radar
  • radar
Did you work the next one?

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