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anonymous

  • 5 years ago

SOMEONE PLEASE HELP! A rectangular yard measuring 40 ft by 71ft is bordered (and surrounded) by a fence. Inside, a walk that is 3 ft wide goes all the way along the fence. Find the area of this walk. Be sure to include the correct unit in your answer.

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  1. anonymous
    • 5 years ago
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    is 40ft the length and 71ft the width of the yard?

  2. anonymous
    • 5 years ago
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    i'm guessing. that is how it is written. so yes.

  3. anonymous
    • 5 years ago
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    it is worded really weird

  4. anonymous
    • 5 years ago
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    ok then, if 40ft is the length, u can multiply that times the width of the walk, so 3 ft, 40*3= 120...i think that would be the area 120 sq ft

  5. anonymous
    • 5 years ago
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    it said that was incorrect

  6. anonymous
    • 5 years ago
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    it will show me how to do it. and iwill tell u. then will u heelp me with the next 2 problems like this one?

  7. anonymous
    • 5 years ago
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    sure ill try to help u

  8. anonymous
    • 5 years ago
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    We start by drawing a rectangle representing the fence surrounding the yard. Inside the fence, we draw a wide walk going along the fence. inner rectangle's length is the yard length twice the walk width. so 71-3-3=65 ft and the width is 40-3-3=34 ft

  9. anonymous
    • 5 years ago
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    since the walk is the region between the 2 rectangles..it's area is the area of the larger rectangle minus the area of the smaller rectangle. so a=40x71-34x65 =2840-2210 =630 ft ^2

  10. anonymous
    • 5 years ago
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    follow? bc it's kinda confusing to me.

  11. anonymous
    • 5 years ago
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    yes, i think i follow

  12. anonymous
    • 5 years ago
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    ok, i got it :)

  13. anonymous
    • 5 years ago
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    it sounds more like a rectangular box?

  14. anonymous
    • 5 years ago
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    i know. this thing is so stupid..but i think i have the hang of it now.

  15. radar
    • 5 years ago
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    It kinda makes sense, otherwise you might include the corners twice.

  16. radar
    • 5 years ago
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    Did you work the next one?

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