SOMEONE PLEASE HELP!
A rectangular yard measuring 40 ft by 71ft is bordered (and surrounded) by a fence. Inside, a walk that is 3 ft wide goes all the way along the fence. Find the area of this walk. Be sure to include the correct unit in your answer.
Stacey Warren - Expert brainly.com
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is 40ft the length and 71ft the width of the yard?
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ok then, if 40ft is the length, u can multiply that times the width of the walk, so 3 ft, 40*3= 120...i think that would be the area 120 sq ft
it said that was incorrect
it will show me how to do it. and iwill tell u. then will u heelp me with the next 2 problems like this one?
sure ill try to help u
We start by drawing a rectangle representing the fence surrounding the yard.
Inside the fence, we draw a wide walk going along the fence.
inner rectangle's length is the yard length twice the walk width. so 71-3-3=65 ft and the width is 40-3-3=34 ft
since the walk is the region between the 2 rectangles..it's area is the area of the larger rectangle minus the area of the smaller rectangle.
=630 ft ^2
follow? bc it's kinda confusing to me.
yes, i think i follow
ok, i got it :)
it sounds more like a rectangular box?
i know. this thing is so stupid..but i think i have the hang of it now.
It kinda makes sense, otherwise you might include the corners twice.