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anonymous

  • 5 years ago

Find the equation of a circle given its point in the centre being (1,2)

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  1. anonymous
    • 5 years ago
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    hey newton, how do you copy and paste someone else's latex

  2. anonymous
    • 5 years ago
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    (x-1)sqare+(x-2)square=r square

  3. anonymous
    • 5 years ago
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    As far as I know, you can't on here, unless they send it to you before they render it in LaTeX.

  4. anonymous
    • 5 years ago
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    \[(x-1)^2 + (y-2)^2 = r^2 \]

  5. anonymous
    • 5 years ago
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    how annoying

  6. anonymous
    • 5 years ago
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    Then how do we go about solving for r?

  7. anonymous
    • 5 years ago
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    well someone send an email to the coders

  8. anonymous
    • 5 years ago
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    You can't solve for r... a circle with centre 1,2 is not unique.

  9. anonymous
    • 5 years ago
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    Wait couldn't we just use another point close to it, say (1,3) and solve for r?

  10. anonymous
    • 5 years ago
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    r is radius boy it s given ithink

  11. anonymous
    • 5 years ago
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    You could try. It wouldn't work (at all), but you could try.

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spraguer (Moderator)
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