A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 5 years ago

how do i find all solutions to the system y=-x squared-4x+12 and y=-2x+4

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    u can set them equal to eachother, that's one way u can go at it -x^2 -4x+12=-2x+4 (move stuff over) -x^2-4x+12+2x-4=0 (add 2x, subtract 4 from both sides) -x^2-2x+8=0 (combine like terms) x^2+2x-8=0 (it makes it easier to take out the negative sign infront of the x^2) factor the eqn and u get (x+4)(x-2) to find the individual x values, set each part equal to 0 x+4=0, x-2=0 so ur x values would be x=-4, 2

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.