Find the roots of the quadratic equation x2 − 8x + 8 = 0 . x1 = x2 =

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Find the roots of the quadratic equation x2 − 8x + 8 = 0 . x1 = x2 =

Mathematics
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\[(-b \pm \sqrt{b ^{2}-4ac)}/2a\]
b=-8, a=1, and c=8
I prefer: \[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \] \.[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \]

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that's more betterr
6.828, 1.17157
Car2021, You have everything you need to solve it, including some answers that you can use as a check.
ok so if i have \[8\pm 4\sqrt{2}/2\]..how would i solve that?
You could simplify further and get \[4\pm 2\sqrt{2}\]
Solve for both roots
Use the + value for one root, then use the - for the other \[4-2\sqrt{2}\]
\[4+2\sqrt{2}\]
soo would it be 2 sqrt 2 for one and 6 sqrt 2 for the other
Almost, first solve for the 2 times the square root of 2. this should give you a value of 2.828. Now with that you will use to get the two roots. First add that to 4, that will be one root. Then use it again subtracting it from four getting the second root.
Let me know what you get.
if, ax^2 + bx + c is a quadratic equation then we can find its roots by using a formula http://upload.wikimedia.org/math/3/e/a/3ea647783b5121989cd87ca3bb558916.png now try to solve it yourself. don't just go for the solution.
He has solved it down to the point of\[4\pm 2\sqrt{2}\]
radar ..when u get done will you help me?
or chatindia..lol
Yes, would be glad too, providing I can. I am just reviewing math from the past lol
lol okay thank you! :))
Is your problem already posted laurenlynn?
yes
it's the one that says PLEASE HELP ME!!! at the top..haha
O.K. I will look for it.
Car2021, I believe you have this problem whipped, cantorset has given you the actual answers in an early post of this thread. Good luck
what's the problem you are getting in solving this question. this latex code doesn't display in my phone. i can't understand this latex codes.

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