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anonymous
 5 years ago
is this a function?
anonymous
 5 years ago
is this a function?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha sorry i still need to attach the file!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A function need to pass a verticle line test

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know but i cant tell if this one does.. i graph it on my calculator but its not working

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You calculator will only graph the top half

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Plot a second function with  infront of it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=Plot%5B {Sqrt%5B%28x%2B2%29%2F2%5D%2CSqrt%5B%28x%2B2%29%2F2%5D}%5D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I posted the link to my plot, can you see it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is \[\sqrt{x}1 \] a function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=Plot%5B {Sqrt%5B%28x%2B2%29%2F2%5D%2CSqrt%5B%28x%2B2%29%2F2%5D}%5D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. the link is only partly blue so i dont think its working

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just copy/paste the whole thing to your address bar

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay now i see it!! but i still cant tell if it is a function. is it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is not since it does not pass the verticle line test. Blue(top) and purple plot(bottom)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0My two cent. If a teacher gives you a function, as a equation than it is probably a function. If the teacher graphs it for you than it is probably NOT a function, but in both cases you need to verify it with the vertical line test. It is extremely hard to make an equation that is not a function.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y = + sqrt x is not a function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its + sqrt x 1 though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well its the same idea

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so for sure it is not a function? also, what is the domain of 3x^2+4x+2? os ot a;; real numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it all real numbers**

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all real numbers, because there is no reason to restrict the domain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for example y = 1/x , we cant have division by zero when x = 0, so x=0 is not in the domain. but the rest of real numbers is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, so is \[\sqrt{x}1 \] a function or not??? i need a final answer!!!!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its a function, but when you have + , it isn't a function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is 5/9 (F32) a function
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