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anonymous
 5 years ago
what is the equation of the tangent line to y= e^4x + tan1 (x) at x=0
anonymous
 5 years ago
what is the equation of the tangent line to y= e^4x + tan1 (x) at x=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tangent line = derivative at the point for slope, then just use the point. So derivative of this is 4e^(4x)+1/(x^2+1). At x=0 it is 4+1=5. The point is then (0,0). So use yy1=m(xx1) to get y0=5(x0), or y=5.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0the point is (0,1) that we are trying to find the tangent line

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Point is actually (0,1), so line is y1=5(x0)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I didn't know what the y point was how do you find it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Plug in x=0 into the original equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So is e^4x 1 then? Thats what I'm confused about

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0just like 5^(0)=1 and 2^(0)=1

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0if tan^(1)(0)=s then tan(s)=0 what value of s betweeen pi/2 and pi/2 makes this expressions true

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok got it now... thanks so much

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0when i said expression i mean equation lol
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