anonymous
  • anonymous
The lim h->0 abs(x+h)-abs(x)/h at x=3 is?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
can i see a pic of you, i will answer your question
anonymous
  • anonymous
uhm a pic of me?
myininaya
  • myininaya
1

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anonymous
  • anonymous
yeah
anonymous
  • anonymous
why?
anonymous
  • anonymous
it helps me do math
anonymous
  • anonymous
keeps my mind on the prize,
myininaya
  • myininaya
if x>0 then |x+h|=x+h and |x|=x if x<0 then |x+h|=-(x+h) and |x|=-x but we have the first version so the answer is 1
anonymous
  • anonymous
so i don't put 0 in for h?
myininaya
  • myininaya
h/h=1
anonymous
  • anonymous
the derivative is not defined for absolute value at x = 0
anonymous
  • anonymous
oh but near x = 3, thats fine
anonymous
  • anonymous
right the answer is 1
anonymous
  • anonymous
By the definition of a derivative, this is derivative of lxl at x=3. Don't you agree myininaya?
anonymous
  • anonymous
look at the graph of y = | x|
anonymous
  • anonymous
its a V, it has two branches , the negative branch has slope -1, the positive branch has +1 slope
myininaya
  • myininaya
bur since there is a sharp turn at x=0 then f' dne at x=0
myininaya
  • myininaya
so for all x>0 f'(x)=1 for all x<0 f'(x)=-1 f'(0) DNE
anonymous
  • anonymous
Yeah, I agree.
myininaya
  • myininaya
yeah we agree on something lol
anonymous
  • anonymous
:)
anonymous
  • anonymous
anwar, i proved the lim problem
anonymous
  • anonymous
You did?
anonymous
  • anonymous
its a direct result of using the definition of a limit
anonymous
  • anonymous
yeah
anonymous
  • anonymous
How?
anonymous
  • anonymous
You did it or someone did it and you claimed it's you, as you did with mine? :P
anonymous
  • anonymous
well someone said to state the definition of a limit
anonymous
  • anonymous
and then i looked at it, and voila
anonymous
  • anonymous
I see. Btw, I was just kidding.
anonymous
  • anonymous
oh i see, dark humor
anonymous
  • anonymous
LETS do the proof

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