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anonymous

  • 5 years ago

The lim h->0 abs(x+h)-abs(x)/h at x=3 is?

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  1. anonymous
    • 5 years ago
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    can i see a pic of you, i will answer your question

  2. anonymous
    • 5 years ago
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    uhm a pic of me?

  3. myininaya
    • 5 years ago
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    1

  4. anonymous
    • 5 years ago
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    yeah

  5. anonymous
    • 5 years ago
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    why?

  6. anonymous
    • 5 years ago
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    it helps me do math

  7. anonymous
    • 5 years ago
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    keeps my mind on the prize,

  8. myininaya
    • 5 years ago
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    if x>0 then |x+h|=x+h and |x|=x if x<0 then |x+h|=-(x+h) and |x|=-x but we have the first version so the answer is 1

  9. anonymous
    • 5 years ago
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    so i don't put 0 in for h?

  10. myininaya
    • 5 years ago
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    h/h=1

  11. anonymous
    • 5 years ago
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    the derivative is not defined for absolute value at x = 0

  12. anonymous
    • 5 years ago
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    oh but near x = 3, thats fine

  13. anonymous
    • 5 years ago
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    right the answer is 1

  14. anonymous
    • 5 years ago
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    By the definition of a derivative, this is derivative of lxl at x=3. Don't you agree myininaya?

  15. anonymous
    • 5 years ago
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    look at the graph of y = | x|

  16. anonymous
    • 5 years ago
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    its a V, it has two branches , the negative branch has slope -1, the positive branch has +1 slope

  17. myininaya
    • 5 years ago
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    bur since there is a sharp turn at x=0 then f' dne at x=0

  18. myininaya
    • 5 years ago
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    so for all x>0 f'(x)=1 for all x<0 f'(x)=-1 f'(0) DNE

  19. anonymous
    • 5 years ago
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    Yeah, I agree.

  20. myininaya
    • 5 years ago
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    yeah we agree on something lol

  21. anonymous
    • 5 years ago
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    :)

  22. anonymous
    • 5 years ago
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    anwar, i proved the lim problem

  23. anonymous
    • 5 years ago
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    You did?

  24. anonymous
    • 5 years ago
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    its a direct result of using the definition of a limit

  25. anonymous
    • 5 years ago
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    yeah

  26. anonymous
    • 5 years ago
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    How?

  27. anonymous
    • 5 years ago
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    You did it or someone did it and you claimed it's you, as you did with mine? :P

  28. anonymous
    • 5 years ago
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    well someone said to state the definition of a limit

  29. anonymous
    • 5 years ago
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    and then i looked at it, and voila

  30. anonymous
    • 5 years ago
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    I see. Btw, I was just kidding.

  31. anonymous
    • 5 years ago
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    oh i see, dark humor

  32. anonymous
    • 5 years ago
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    LETS do the proof

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