anonymous 5 years ago ∫[0,1,(3x^(2)+2)^(2)x,] Evaluate the definite integrals

1. myininaya

$\int\limits_{0}^{1}x(3x^2+2)^{2}dx$

2. myininaya

try to let u=3x^2+2 then du=6x dx or (du)/6=xdx since x=1, then u=3(1)^2+2=5 since x=0, then u=3(0)^2+2=2 so we have $\int\limits_{2}^{5}(1/6)*u^{2} du$

3. anonymous

So I don't need to do anything with the exponent on the outside the parenthesis which was actually sipposed to be a three not a two?