1. anonymous

ok

2. anonymous

$\sqrt[4]{32y^13}$

3. anonymous

32 = 2 x 2 x 2 x 2

4. anonymous

i left out one 2

5. anonymous

its y raised to the 13th

6. anonymous

im guessing im factoring it?

7. anonymous

are you trying to solve for y?

8. anonymous

no i think you are trying to simplify the expression

9. anonymous

i was using prime factorization

10. anonymous

right simplify

11. anonymous

so you have 32 factored to 2^5, so take away 16 from inside the radical and leave in one 2 as for y, you have y^3 outside the radical and one y inside, since (y^3)^4 * y = y^13

12. anonymous

im pretty sure it is 2y^3*radical4(2y)

13. anonymous

so its 32^(1/4)*y^(13/4)*3^(1/4)

14. anonymous

its a 4 outside the radical and 32y^13 on the inside

15. anonymous

Factor completely: 6b^2+4a-8b-3ab

16. anonymous

wait, ok your previous expression was messed up, can you re type it?