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anonymous
 5 years ago
If integral from 0,2 (2x^3kx^2+2x)dx=12, then k must be?
I've tried working it out several times but I still don' get the right answer.
anonymous
 5 years ago
If integral from 0,2 (2x^3kx^2+2x)dx=12, then k must be? I've tried working it out several times but I still don' get the right answer.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{?}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{2} (2x^3kx^2+2k) dx =12\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{2} 2x^3  kx^2 + 2k = 12 \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0= 2x^4/4  kx^3/3 +2kx from 2 to 0 , = 12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02(2^4)/4  k(2^3)/3 + 2(k)(2)  [ 0 + 0 + 0 ] = 12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you get that so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah... instead of adding one to the power I was just finding the derivative..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well we are integrating, correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah :) thanks... let me see if i get it now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey can u help me in another one real quick? sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{} (\sec^2x)(\tan ^2x)dx=\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i got integral u^2 du
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