A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
anonymous
 5 years ago
How to find the arclength of
(1/16)x^4 + (1/2)x^2 on the interval of [1,2]?
anonymous
 5 years ago
How to find the arclength of (1/16)x^4 + (1/2)x^2 on the interval of [1,2]?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have the function, now apply the general form of your arc length equation: \[L = \int\limits \ { \sqrt{1 + (\frac{dy}{dx})^2} } dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The derivative of the function shouldn't be too difficult to find, so once you have that, square it, add one, take the square root of the entire expression and integrate w.r.t. x between 1 and 2 to get the value for the length.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.