(3x+2)/(x-5)≤ 0

- anonymous

(3x+2)/(x-5)≤ 0

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- schrodinger

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- anonymous

ohhhh, nice pic

- anonymous

wowowowowowo

- anonymous

seriously?

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## More answers

- anonymous

wowowowowowow chick a bow wow

- anonymous

you have two cases

- anonymous

-_-

- anonymous

+ / - and - / +

- anonymous

:)

- anonymous

ok so far?

- anonymous

yupp

- anonymous

those two cases will make it < = 0

- anonymous

so first case + / - , we have (3x + 2) >= 0 and denominator < 0

- anonymous

aren't they both less than 0?

- anonymous

no then you will have negative/ negative wich is positive

- anonymous

gotcha

- anonymous

remember denominator cannot equal zero

- anonymous

thats why x-5 < 0 , not x-5 <= 0

- anonymous

now give me medal,

- anonymous

not until you show me how to do this problem

- anonymous

awwwww

- anonymous

To get cantorset's attention, just have a pretty picture :P

- anonymous

yeah, so he can be an retriceand not focus on the task at hand.

- anonymous

He's trying to get achievements and medals, nothing more.
Do you still need help, alexghe92?

- anonymous

yes please, sorry for the confusion before.

- anonymous

sorry im multitasking

- anonymous

I got a medal for my answer here :D

- anonymous

whoa, why am i an retrice

- anonymous

although I don't deserve it :(

- anonymous

you are a jerk. what makes you so special i have to answer this

- anonymous

what gives you this sense of entitlement. im done here

- anonymous

i gave you plenty of information , yuo just want me to spoon feed this

- anonymous

good luck

- anonymous

retrice

- anonymous

k bye.

- anonymous

I don't think she needs you anymore, since she has Quantum :P

- anonymous

Okay, so right now, you can let it behave as though it's an equation and say that (3x+2)/(x-5)= 0 (for simplicity's sake). Then, multiply both sides by x-5, but on both sides it just disappears, leaving you with 3x+2 = 0. Subtract two, and divide by 3, to get x ≤ -2/3, after replacing the "=" with "≤" (in this case, the direction of the inequality doesn't change, so you don't lose any information by converting between the two. Hope that helped

- anonymous

that wont work quantum

- anonymous

lol

- anonymous

How?

- anonymous

scroll up , there are two cases

- anonymous

+ / - and - / + for when the inequality < = 0

- anonymous

i started the first case

- anonymous

but im just an retrice what do i know

- anonymous

If you're going to type a response, type it in one swoop, don't just break it up into several just to get your achievements.

- anonymous

you have more cases than just x < = -2/3, its a compound inequality

- anonymous

quantum, well im not getting paid

- anonymous

oh god, i just squashed my nads, i was crossing legs

- anonymous

cant breathe

- anonymous

brb, im answering other questions btw

- anonymous

youre right, the second answer is 5.

- anonymous

Alright, I think I made a mistake with my sign change from the l.e. to =. Because you had something in the denominator, it does flip to "greater than or equal to", and thus you have x is greater than or equal to -2/3. And, to have the case that cantorset was talking about, you have to have some region where x-5 < 0, which gives you x < 5. So, we now know that x satisfies the expression anywhere in between -2/3 and 5, including -2/3, and excluding 5.

- anonymous

(It's been such a long time since I worked directly with inequalities! xD )

- anonymous

youve been a bunch of help though, I haven't done these problems since the beginning of the semester and my final exam is on tuesday so I just needed to refresh. Thank you!

- anonymous

Glad to help. :)

- anonymous

so you guys didnt answer this , i will answer it, one sec

- anonymous

-2=3x since (3x+2)/(x-5)\[\le\]0
multiply the (x-5) on each side, on the left side it cancels out, on the right side its 0 (0 times any number is 0.) then remove the parenthesis, subtract two, which gets you 3x=-2. you can simplify this further, which will get you a decimal. (which, im also not going to do.)

- anonymous

Cantorset, it's answered. Definitively.

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