(3x+2)/(x-5)≤ 0

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(3x+2)/(x-5)≤ 0

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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ohhhh, nice pic
wowowowowowo
seriously?

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Other answers:

wowowowowowow chick a bow wow
you have two cases
-_-
+ / - and - / +
:)
ok so far?
yupp
those two cases will make it < = 0
so first case + / - , we have (3x + 2) >= 0 and denominator < 0
aren't they both less than 0?
no then you will have negative/ negative wich is positive
gotcha
remember denominator cannot equal zero
thats why x-5 < 0 , not x-5 <= 0
now give me medal,
not until you show me how to do this problem
awwwww
To get cantorset's attention, just have a pretty picture :P
yeah, so he can be an retriceand not focus on the task at hand.
He's trying to get achievements and medals, nothing more. Do you still need help, alexghe92?
yes please, sorry for the confusion before.
sorry im multitasking
I got a medal for my answer here :D
whoa, why am i an retrice
although I don't deserve it :(
you are a jerk. what makes you so special i have to answer this
what gives you this sense of entitlement. im done here
i gave you plenty of information , yuo just want me to spoon feed this
good luck
retrice
k bye.
I don't think she needs you anymore, since she has Quantum :P
Okay, so right now, you can let it behave as though it's an equation and say that (3x+2)/(x-5)= 0 (for simplicity's sake). Then, multiply both sides by x-5, but on both sides it just disappears, leaving you with 3x+2 = 0. Subtract two, and divide by 3, to get x ≤ -2/3, after replacing the "=" with "≤" (in this case, the direction of the inequality doesn't change, so you don't lose any information by converting between the two. Hope that helped
that wont work quantum
lol
How?
scroll up , there are two cases
+ / - and - / + for when the inequality < = 0
i started the first case
but im just an retrice what do i know
If you're going to type a response, type it in one swoop, don't just break it up into several just to get your achievements.
you have more cases than just x < = -2/3, its a compound inequality
quantum, well im not getting paid
oh god, i just squashed my nads, i was crossing legs
cant breathe
brb, im answering other questions btw
youre right, the second answer is 5.
Alright, I think I made a mistake with my sign change from the l.e. to =. Because you had something in the denominator, it does flip to "greater than or equal to", and thus you have x is greater than or equal to -2/3. And, to have the case that cantorset was talking about, you have to have some region where x-5 < 0, which gives you x < 5. So, we now know that x satisfies the expression anywhere in between -2/3 and 5, including -2/3, and excluding 5.
(It's been such a long time since I worked directly with inequalities! xD )
youve been a bunch of help though, I haven't done these problems since the beginning of the semester and my final exam is on tuesday so I just needed to refresh. Thank you!
Glad to help. :)
so you guys didnt answer this , i will answer it, one sec
-2=3x since (3x+2)/(x-5)\[\le\]0 multiply the (x-5) on each side, on the left side it cancels out, on the right side its 0 (0 times any number is 0.) then remove the parenthesis, subtract two, which gets you 3x=-2. you can simplify this further, which will get you a decimal. (which, im also not going to do.)
Cantorset, it's answered. Definitively.

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