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anonymous

  • 5 years ago

Please answer! Find distance from -5+4i to 0

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  1. anonymous
    • 5 years ago
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    wouldn't you just set it equal to 0? If that is the case it is 5/4

  2. dumbcow
    • 5 years ago
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    use distance formula d^2 = (-5)^2 + 4^2

  3. radar
    • 5 years ago
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    \[\sqrt{(-5^{2}+(4i)^{2}}\] would this do it?

  4. radar
    • 5 years ago
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    \[\sqrt{25+(-16)}=\sqrt{9}=\pm3\]

  5. anonymous
    • 5 years ago
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    But it asks for the distance from 0 to (-5+4i) is that still right

  6. radar
    • 5 years ago
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    It is a complex number containing a real component (-5) and the imaginary component 4i

  7. radar
    • 5 years ago
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    Helllllp

  8. myininaya
    • 5 years ago
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    http://www.mathwarehouse.com/algebra/complex-number/absolute-value-complex-number.php

  9. anonymous
    • 5 years ago
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    I get it now! Thanks

  10. myininaya
    • 5 years ago
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    sqrt(5^2+4^2)=sqrt(25+16)=sqrt(41)

  11. radar
    • 5 years ago
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    I see where I went astray, I inludec i squared which is a -1, when I should of ignored the fact there was an i, as I was actually getting the absolute value.

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