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anonymous

  • 5 years ago

the population of the world, as of august 12, 2000, was estimated by the U.S. Census bureau to be about 5.779 billion people and growing at a rate of 1.38%. a. what was the population on august 12, 1800? b. what should the population be today, april 15, 2011? c. when will the population be 6.5 billion?

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  1. anonymous
    • 5 years ago
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    does anyone know how to do this. i am soo confused

  2. dumbcow
    • 5 years ago
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    \[P _{t} =P _{0}(1+r)^{t}\] r = growth rate = .0138 For A) setup would be \[5.779=P _{0}(1.0138)^{200}\] solve for P

  3. anonymous
    • 5 years ago
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    do you divide the side next to p to the 5.779

  4. dumbcow
    • 5 years ago
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    yes

  5. anonymous
    • 5 years ago
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    where did the 200 come from

  6. dumbcow
    • 5 years ago
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    the number of years from 1800 to 2000

  7. anonymous
    • 5 years ago
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    ok

  8. anonymous
    • 5 years ago
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    do you know how to do the other 2

  9. dumbcow
    • 5 years ago
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    B) \[P _{t}=5.779(1.0138)^{10.67}\] 10.67 is aPPROXIMATELY NUM OF years since august 2000 C) \[6.5 = 5.779(1.0138)^{t}\] solve for t using logs

  10. anonymous
    • 5 years ago
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    ok thanks

  11. dumbcow
    • 5 years ago
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    your welcome

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