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anonymous
 5 years ago
find the first and second derivative of cuberootx/
(1x)
anonymous
 5 years ago
find the first and second derivative of cuberootx/ (1x)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know its quotient rule but i can't seem to get it to work out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, so you can rewrite it as (1x) ^ 1/3. Use chain rule once to get 1/3 * 1 * (1x) ^ (1/3  1). Lather, rinse, repeat. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For the second derivative, yeah, you shouldn't need quotient rule...you can continue using chain rule to your heart's delight.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ohhhhh, didn't see the x before the fraction...sorry. :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[3]{x}/(1x)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I see now. You can assign a general term to the numerator, and to the denominator  like u, and v, respectively. The quotient rule goes something like d/dx (u/v) = ( v * u'  u * v') / v^2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0...it's going to become very ugly, very quickly. :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know! I've tried working it out multiple times times with no succes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright, I understand where it's easy to go wrong here...it's a lot of terms being tossed about, and to keep track of; let's try going through the first derivative, and you can try to do the second (give yourself some space!). d/dx (cbrt(x) / (1x) ) = ( (1x) * 1/3 * x^(2/3)  cbrt(x) * 1 ) / (1x)^2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0...let me know if you see any careless mistakes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, now...get your self a biiiig piece of paper...and churn out the second. :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you also write the first as [1x+x^(1/3)]/ [3x^(2/3)(1x)^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0looks good! and the best part is, i have to find the zeros of both because i have use that information to draw a graph. whoohoo!
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