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anonymous
 5 years ago
Find f.
f ''(x) = 20x^3 + 12x^2 + 4
f(0) = 3
f(1) = 3
My Answer was x^5+x^42x+3
my answer was wrong, can someone tell me where I went wrong?
anonymous
 5 years ago
Find f. f ''(x) = 20x^3 + 12x^2 + 4 f(0) = 3 f(1) = 3 My Answer was x^5+x^42x+3 my answer was wrong, can someone tell me where I went wrong?

This Question is Closed

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2f'(x)=20x^4/4+12x^3/3+4x+C=5x^4+4x^3+4x+C f(x)=5x^5/5+4x^4/4+4x^2/2+Cx+D=x^5+x^4+2x^2+Cx+D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what math are you in Calc I or II

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay I used integration, I'm assuming that you know how?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2f(0)=D=3 f(1)=1+1+2+C+3=3 so C=4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so take the integral of f double prime (c)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you get 20x^4/4 + 12x^3/3 + 4x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then simplify and do it once more

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Plug f(0) in for x and set it equal to 3 makes D= 3 Plug f(1) in for x and set it equal to 3 makes C= 2 plugging those in was wrong

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2you are missing 2x^2 in f(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0myininaya solved it already

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2f(x)=x^5+x^4+2x^2+Cx+D
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