how do you find the inverse of y=x^2 +2

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how do you find the inverse of y=x^2 +2

Mathematics
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get x by itself y-2 = x^2 sqrt(y-2) = x
i thought you had to switch x and y. so you would have x=y^2 +2 then you subtract 2 so its x-2=y^2
either way works you will still get f^-1 = sqrt(x-2)

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Other answers:

so the answer is ?
y= sqrt of x-2?
correct
thank you. can you help me some more.?
what do you have
the direcxtions say find ^-1 and the doman and range of f (-1) determine where f^-1 is a function. and the problem is f(x) sqrt 3x
ok flip x and y x = sqrt(3y) solve for y
so the anser is x^2 = y
dont forget about the 3 x^2 = 3y (x^2/3) = y now what is domain and range
domain is all real. and range idk
good range is all possible y-values since x is squared, all the negative x's we put in become positive right? so our y value is always positive
ohh. so its y is greater than 0 ?
correct, well equal to y>=0
oh em gee thank you. :]
your welcome

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