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anonymous

  • 5 years ago

how do you find the inverse of y=x^2 +2

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  1. dumbcow
    • 5 years ago
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    get x by itself y-2 = x^2 sqrt(y-2) = x

  2. anonymous
    • 5 years ago
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    i thought you had to switch x and y. so you would have x=y^2 +2 then you subtract 2 so its x-2=y^2

  3. dumbcow
    • 5 years ago
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    either way works you will still get f^-1 = sqrt(x-2)

  4. anonymous
    • 5 years ago
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    so the answer is ?

  5. anonymous
    • 5 years ago
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    y= sqrt of x-2?

  6. dumbcow
    • 5 years ago
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    correct

  7. anonymous
    • 5 years ago
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    thank you. can you help me some more.?

  8. dumbcow
    • 5 years ago
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    what do you have

  9. anonymous
    • 5 years ago
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    the direcxtions say find ^-1 and the doman and range of f (-1) determine where f^-1 is a function. and the problem is f(x) sqrt 3x

  10. dumbcow
    • 5 years ago
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    ok flip x and y x = sqrt(3y) solve for y

  11. anonymous
    • 5 years ago
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    so the anser is x^2 = y

  12. dumbcow
    • 5 years ago
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    dont forget about the 3 x^2 = 3y (x^2/3) = y now what is domain and range

  13. anonymous
    • 5 years ago
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    domain is all real. and range idk

  14. dumbcow
    • 5 years ago
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    good range is all possible y-values since x is squared, all the negative x's we put in become positive right? so our y value is always positive

  15. anonymous
    • 5 years ago
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    ohh. so its y is greater than 0 ?

  16. dumbcow
    • 5 years ago
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    correct, well equal to y>=0

  17. anonymous
    • 5 years ago
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    oh em gee thank you. :]

  18. dumbcow
    • 5 years ago
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    your welcome

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