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anonymous

  • 5 years ago

Solve the equation: 3^x+1=1/9

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  1. anonymous
    • 5 years ago
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    you realize that 3^0 is 1 and 1/9 is 3^-2

  2. anonymous
    • 5 years ago
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    3^x+3^0=3^-2

  3. anonymous
    • 5 years ago
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    3^x+1=1/3^2 3^x+1=3^-2 x+1=-2 x=-3

  4. anonymous
    • 5 years ago
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    oh is it 3^(x+1)? no wonder, i was getting worried there

  5. anonymous
    • 5 years ago
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    Acually im not sure but two answers better than one right?

  6. anonymous
    • 5 years ago
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    nah, 3^0 doesn't work out

  7. anonymous
    • 5 years ago
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    that would be unsolvable

  8. anonymous
    • 5 years ago
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    Or it can be solved by log Log(3^x)+log(1)=log(3^-2) xlog3+log1=-2log3 Xlog3=-2log3-log1 X=(-2log3-log1)/log3

  9. anonymous
    • 5 years ago
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    don't think you can do that log(3^x+1) is not log(3^x)+log(1)

  10. anonymous
    • 5 years ago
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    you take the log of both sides, not individual expressions

  11. anonymous
    • 5 years ago
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    Hmmm... Will it does has something wrong but cant find it

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spraguer (Moderator)
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