Solve the equation: 3^x+1=1/9

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Solve the equation: 3^x+1=1/9

Mathematics
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you realize that 3^0 is 1 and 1/9 is 3^-2
3^x+3^0=3^-2
3^x+1=1/3^2 3^x+1=3^-2 x+1=-2 x=-3

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Other answers:

oh is it 3^(x+1)? no wonder, i was getting worried there
Acually im not sure but two answers better than one right?
nah, 3^0 doesn't work out
that would be unsolvable
Or it can be solved by log Log(3^x)+log(1)=log(3^-2) xlog3+log1=-2log3 Xlog3=-2log3-log1 X=(-2log3-log1)/log3
don't think you can do that log(3^x+1) is not log(3^x)+log(1)
you take the log of both sides, not individual expressions
Hmmm... Will it does has something wrong but cant find it

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