anonymous
  • anonymous
42x^(5)y^(6)z^(10) ___________________ 56x^(3)y^(9) anyone have any clue how to do this?!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
if you're still talking about your restrictions then it's simple you have to make sure that the denominator cannot be zero so x and y cannot be zero those are your restrictions
anonymous
  • anonymous
i understand that, but i dont know how to solve it
anonymous
  • anonymous
btw to type fractions you use \frac{numer}{deno} in the equation editor you'll get \frac{2}{4} \[\frac{2}{4} \]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
haha i have no idea how to do that, im not a big computer person i just need to know how to solve this
anonymous
  • anonymous
well...i dont know how you can solve it... but i can simplify it... you'll get \[\frac{42}{56}*\frac{x^2 * z^{10}}{y^3}\] so actually, the restrictions of the simplified version would be y cannot equal to zero

Looking for something else?

Not the answer you are looking for? Search for more explanations.