anonymous
  • anonymous
i have the answer but the problem but no explanation.. i need to know how to solve this. how do i get there. thanks. 4x2 = -8x -1 the answer comes out to this fraction -2 ±√3 ________ 2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
and the problem... here is a picture just in case
1 Attachment
anonymous
  • anonymous
use the quadratic formula after getting all terms on one side 4x2+8x+1 so a=4, b=8, and c=1 plug into qf
anonymous
  • anonymous
did you take a look at the picture? it didnt type out correctly. sorry. i really appreciate your help.

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anonymous
  • anonymous
I understood the problem..do you know the quadratic formula?
anonymous
  • anonymous
not really
anonymous
  • anonymous
ok I will type it out
anonymous
  • anonymous
thank you so much
anonymous
  • anonymous
\[-b \pm \sqrt{b ^{2}-4ac}/2a\]
anonymous
  • anonymous
2a is in the denominator so substitute a, b, and c
anonymous
  • anonymous
\[-8 \pm \sqrt{64-16}/ 8\]
anonymous
  • anonymous
\[-8\pm \sqrt{48}/8 = -8\pm \sqrt{16*3} /8 -8\pm4\sqrt{3} /8\]
anonymous
  • anonymous
I skipped the initial step of plugging in the values for a, b, and c do you get that part?
anonymous
  • anonymous
yes i do thank you
anonymous
  • anonymous
so do you understand it
anonymous
  • anonymous
its for friend, but yes i think so. im passing the info along. thank you for your time.
anonymous
  • anonymous
ok you're very welcome
anonymous
  • anonymous
one last question.. how did you know that the qf was necessary? just in case other problems like these come up. how can i decipher whether i need it or not.
anonymous
  • anonymous
if you can't solve the quadratic equation by factoring then your other options are by completing the square or the quadratic formula
anonymous
  • anonymous
not sure if youre still there, but one thing my friend didnt understand was how it was simplified to the final answer. isnt the 4 outside the square root technically tied to it and you can't really simplify it?
radar
  • radar
The simplification was valid. The 48 inside the radical was factored to 16 and 3, the square root of 16 was accomplished by moving the 4 outside of the radical leaving only the square root of 3 within the radical.
radar
  • radar
The simplification of\[-8\pm(4\sqrt{3})/8=-4(2\pm \sqrt{3})/8=(-2\pm \sqrt{3})/2\]

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